Answer to Problem 6TY The area under the standard normal curves between z = -2.165 and z = -1.35 is 0.0733. Explanation of Solution Given info: The mean and standard deviation of the standard normal distribution is 0 and 1. Calculation: Software procedure: Step-by-step procedure to obtain the area using the MINITAB software: • Choose Graph > Probability Distribution Plot choose View Probability > OK. • From Distribution, choose "Normal' distribution. • Click the Shaded Area tab. • Choose X Value and Middle for the region of the curve to shade. • Enter the X value 1 as-2.165 and X value 2 as -1.35. • Click OK. the MINITAR ftware below

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Hi,

Could you please explain how you found the answer for Z  - 2.165. I tried to look it up using the standard normal distribution table but could not find the answer. Could you please advise how I can graph this on a TI-84 plus CE calculator. Thank you.

Answer to Problem 6TY
The area under the standard normal curves between z = -2.165 and z = -1.35 is 0.0733.
Explanation of Solution
Given info:
The mean and standard deviation of the standard normal distribution is 0 and 1.
Calculation:
Software procedure:
Step-by-step procedure to obtain the area using the MINITAB software:
• Choose Graph > Probability Distribution Plot choose View Probability > OK.
• From Distribution, choose "Normal' distribution.
• Click the Shaded Area tab.
• Choose X Value and Middle for the region of the curve to shade.
• Enter the X value 1 as-2.165 and X value 2 as -1.35.
• Click OK.
Output using the MINITAB software is given below:
Distribution Plot
Normal, Mean 0, StDev 1
Density
0.4-
0.3-
0.2
0.1-
0.0
0.07331
-2.165 -1.35
0
X
From MINITAB output, it can be observe that the area under the standard normal curve between z = -2.165
and z = -1.35 is approximately 0.0733.
Thus, the area under the standard normal curve between z = -2.165 and z = -1.35 is 0.0733.
Transcribed Image Text:Answer to Problem 6TY The area under the standard normal curves between z = -2.165 and z = -1.35 is 0.0733. Explanation of Solution Given info: The mean and standard deviation of the standard normal distribution is 0 and 1. Calculation: Software procedure: Step-by-step procedure to obtain the area using the MINITAB software: • Choose Graph > Probability Distribution Plot choose View Probability > OK. • From Distribution, choose "Normal' distribution. • Click the Shaded Area tab. • Choose X Value and Middle for the region of the curve to shade. • Enter the X value 1 as-2.165 and X value 2 as -1.35. • Click OK. Output using the MINITAB software is given below: Distribution Plot Normal, Mean 0, StDev 1 Density 0.4- 0.3- 0.2 0.1- 0.0 0.07331 -2.165 -1.35 0 X From MINITAB output, it can be observe that the area under the standard normal curve between z = -2.165 and z = -1.35 is approximately 0.0733. Thus, the area under the standard normal curve between z = -2.165 and z = -1.35 is 0.0733.
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From this screen, how do I enter the info? Typing exactly what you gave me resulted in the second image. Thank you.

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Transcribed Image Text:fx > * Σ ? A Q Insert AutoSum Recently Financial Logical Text Date & Lookup & Function Used NORM.S.D... A 0.896298 1 2 DIST() 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 77 B X 7 с V Function Library fx D 0 Math & Time Reference Trig =NORM.S.DIST() E Function Arguments NORM.S.DIST F Formula result = Help on this function Z Cumulative G ... More Functions H Define Name Fx Use in Formula * Name Manager Create from Selection Defined Names I J ↑ ↑ K = number = logical = Returns the standard normal distribution (has a mean of zero and a standard deviation of one). Z is the value for which you want the distribution. L Trace Precedents Trace Dependents Remove Arrows OK M Formula Auditing ? Show Formulas Error Checking ✓ Evaluate Formula N Cancel X O EA 68 Watch Windo P
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Transcribed Image Text:File A1 1 2 3 4 5 fx Σ 0 Insert AutoSum Recently Financial Logical Text Date & Lookup & Math & More Function Used Time Reference Trig Functions 6 7 8 9 10 11 Home Insert Page Layout Formulas Data Review View 12 13 A 0.896298 ; B с Function Library fix D E Help F =NORM.S.DIST(1.35,TRUE)- NORM.S.DIST(-2.165, TRUE) G Tell me what you want to do H Define Name Use in Formula Name Manager Create from Selection Defined Names I J Book1 E K 跟 L
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Follow-up Question

How would I do this step by step in Excel? I went under statistics and norm s dist and still shows as invalid. Online calculators are no help. Thank you. 

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