Overall question: What is the molality of a 3.25 M aqueous solution of ethanol, C2H5OH? The density of the solution is 0.978 g/mL. The molar mass of ethanol is 46.07 g/mol. Assume you have exactly 1.00 L of solution. Step 1: How many moles of ethanol are present in the solution? [?] moles C₂H5OH moles of C₂H₂OH Enter

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## Calculating the Molality of an Aqueous Solution of Ethanol

### Overall Question:
**What is the molality of a 3.25 M aqueous solution of ethanol, C₂H₅OH?**

### Given Data:
- The density of the solution is 0.978 g/mL.
- The molar mass of ethanol is 46.07 g/mol.
- Assume you have exactly 1.00 L of solution.

### Step 1: 
**How many moles of ethanol are present in the solution?**

[ ? ] moles C₂H₅OH

*Input field:*  
- moles of C₂H₅OH  _____________  [Enter]

### Explanation:
The problem statement is part of an exercise to help students understand how to calculate the molality of an aqueous solution given certain parameters. In this exercise, the overall question is about determining the molality of a 3.25 M (molar) ethanol solution, where molarity is defined as moles of solute per liter of solution.

Before solving for molality, it’s important to identify the key data points given:
- The density of the ethanol solution is 0.978 g/mL.
- The molar mass of ethanol (C₂H₅OH) is 46.07 g/mol.
- The volume of the solution is 1.00 L (liter).

### Calculation Process:
1. **Calculate the number of moles of ethanol:**
   Since molarity (M) is given, you can find the total moles of solute (ethanol) based on the volume of the solution.

\[ \text{Moles of C}_2\text{H}_5\text{OH} = \text{Molarity} \times \text{Volume (L)} \]

2. **Input this value:**
   There is an input field to enter the calculated moles of ethanol which will help in the subsequent steps of calculation for determining molality.

By guiding students through this step-by-step problem-solving method, they can learn the process of converting between different concentration units and apply the concepts of density and molar mass.
Transcribed Image Text:## Calculating the Molality of an Aqueous Solution of Ethanol ### Overall Question: **What is the molality of a 3.25 M aqueous solution of ethanol, C₂H₅OH?** ### Given Data: - The density of the solution is 0.978 g/mL. - The molar mass of ethanol is 46.07 g/mol. - Assume you have exactly 1.00 L of solution. ### Step 1: **How many moles of ethanol are present in the solution?** [ ? ] moles C₂H₅OH *Input field:* - moles of C₂H₅OH _____________ [Enter] ### Explanation: The problem statement is part of an exercise to help students understand how to calculate the molality of an aqueous solution given certain parameters. In this exercise, the overall question is about determining the molality of a 3.25 M (molar) ethanol solution, where molarity is defined as moles of solute per liter of solution. Before solving for molality, it’s important to identify the key data points given: - The density of the ethanol solution is 0.978 g/mL. - The molar mass of ethanol (C₂H₅OH) is 46.07 g/mol. - The volume of the solution is 1.00 L (liter). ### Calculation Process: 1. **Calculate the number of moles of ethanol:** Since molarity (M) is given, you can find the total moles of solute (ethanol) based on the volume of the solution. \[ \text{Moles of C}_2\text{H}_5\text{OH} = \text{Molarity} \times \text{Volume (L)} \] 2. **Input this value:** There is an input field to enter the calculated moles of ethanol which will help in the subsequent steps of calculation for determining molality. By guiding students through this step-by-step problem-solving method, they can learn the process of converting between different concentration units and apply the concepts of density and molar mass.
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