Over the years, the mean customer satisfaction rating at a local restaurant has been 65. The restaurant was recently remodeled, and now the management claims the mean customer rating, μ, is not equal to 65. In a sample of 32 customers chosen at random, the mean customer rating is 76.2. Assume that the population standard deviation of customer ratings is 22.8. Is there enough evidence to support the claim that the mean customer rating is different from 65? Perform a hypothesis test, using the 0.10 level of significance. (a) State the null hypothesis Ho and the alternative hypothesis H₁. Ho: H₁:0 • 20.05 is the value that cuts off an area of 0.05 in the right tail. H Standard Normal Distribution Step 1: Select one-tailed or two-tailed. O One-tailed Two-tailed O

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
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Step 3: Enter the test statistic.
(Round to 3 decimal places.)
0.1-
X
(c) Based on your answer to part (b), choose what can be concluded, at the 0.10 level of significance, about the claim made by the management.
O Since the value of the test statistic lies in the rejection region, the null hypothesis is rejected. So, there is enough
evidence to support the claim that the mean customer rating is not equal 65.
O Since the value of the test statistic lies in the rejection region, the null hypothesis is not rejected. So, there is not
enough evidence to support the claim that the mean customer rating is not equal 65.
O Since the value of the test statistic doesn't lie in the rejection region, the null hypothesis is rejected. So, there is
enough evidence to support the claim that the mean customer rating is not equal 65.
O Since the value of the test statistic doesn't lie in the rejection region, the null hypothesis is not rejected. So, there is
not enough evidence to support the claim that the mean customer rating is not equal 65.
Transcribed Image Text:Step 3: Enter the test statistic. (Round to 3 decimal places.) 0.1- X (c) Based on your answer to part (b), choose what can be concluded, at the 0.10 level of significance, about the claim made by the management. O Since the value of the test statistic lies in the rejection region, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean customer rating is not equal 65. O Since the value of the test statistic lies in the rejection region, the null hypothesis is not rejected. So, there is not enough evidence to support the claim that the mean customer rating is not equal 65. O Since the value of the test statistic doesn't lie in the rejection region, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean customer rating is not equal 65. O Since the value of the test statistic doesn't lie in the rejection region, the null hypothesis is not rejected. So, there is not enough evidence to support the claim that the mean customer rating is not equal 65.
Over the years, the mean customer satisfaction rating at a local restaurant has been 65. The restaurant was recently remodeled, and now the management
claims the mean customer rating, μ, is not equal to 65. In a sample of 32 customers chosen at random, the mean customer rating is 76.2. Assume that the
population standard deviation of customer ratings is 22.8.
Is there enough evidence to support the claim that the mean customer rating is different from 65? Perform a hypothesis test, using the 0.10 level of
significance.
(a) State the null hypothesis Ho and the alternative hypothesis H₁.
Ho:
H₁:0
• 20.05 is the value that cuts off an area of 0.05 in the right tail.
H
Standard Normal Distribution
Step 1: Select one-tailed or two-tailed.
O One-tailed
Two-tailed
O<O OSO
OZO
ロ=ロ
X
x
• The test statistic has a normal distribution and the value is given by z=
(b) Perform a hypothesis test. The test statistic has a normal distribution (so the test is a "Z-test"). Here is some other information to help you with your
test.
x-μ
O
√n
04
O<O
0.3+
0#0
Transcribed Image Text:Over the years, the mean customer satisfaction rating at a local restaurant has been 65. The restaurant was recently remodeled, and now the management claims the mean customer rating, μ, is not equal to 65. In a sample of 32 customers chosen at random, the mean customer rating is 76.2. Assume that the population standard deviation of customer ratings is 22.8. Is there enough evidence to support the claim that the mean customer rating is different from 65? Perform a hypothesis test, using the 0.10 level of significance. (a) State the null hypothesis Ho and the alternative hypothesis H₁. Ho: H₁:0 • 20.05 is the value that cuts off an area of 0.05 in the right tail. H Standard Normal Distribution Step 1: Select one-tailed or two-tailed. O One-tailed Two-tailed O<O OSO OZO ロ=ロ X x • The test statistic has a normal distribution and the value is given by z= (b) Perform a hypothesis test. The test statistic has a normal distribution (so the test is a "Z-test"). Here is some other information to help you with your test. x-μ O √n 04 O<O 0.3+ 0#0
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