Output Example Default Constructor: 0/1 Single Parameter Constructor: 2/1 Dual Parameter Constructor: 1/3 Accessors / Mutators: 3/12 GCD of the last fraction: 3 GCD of 40 and 24: 8 LCM of the last fraction: 12 LCM of 3 and 5: 15 Reducing the last fraction: 1/4

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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help with c++...pste indented code with the same output given plzz

Output Example
Default Constructor: 0/1
Single Parameter Constructor: 2/1
Dual Parameter Constructor: 1/3
Accessors / Mutators: 3/12
GCD of the last fraction: 3
GCD of 40 and 24: 8
LCM of the last fraction: 12
LCM of 3 and 5: 15
Reducing the last fraction: 1/4
Transcribed Image Text:Output Example Default Constructor: 0/1 Single Parameter Constructor: 2/1 Dual Parameter Constructor: 1/3 Accessors / Mutators: 3/12 GCD of the last fraction: 3 GCD of 40 and 24: 8 LCM of the last fraction: 12 LCM of 3 and 5: 15 Reducing the last fraction: 1/4
1. Implement a Rational Number class with the following specifications.
Data members
a) numerator and denominator
Functions
a) Constructors:
1) default constructor
2) single parameter constructor to create numerator/1
3) dual parameter constructor to create numerator/denominator
4) Use constructor delegation across all constructors.
b) Accessors and Mutators for both data members.
c) Static recursive GCD function using Euclid's algorithm.
d) Static LCM function for two numbers.
e) Reduce function simplify a rational number. This function modifies its calling
object.
f) Your program should work with the supplied driver program.
Notes
LCM (Least Common Multiple)
This function returns the smallest multiple of a and b.
Step 1: Multiply a and b to find a common multiple.
Step 2: Divide the common multiple by the GCD of a and b.
Step 3: Return the result of Step 2.
Reduce:
This function reduces a fraction to simplest terms (i.e. 9/12 to 3/4).
Step 1: Find the GCD of the numerator and denominator.
Step 2: Divide the numerator by GCD and store as the new numerator.
Step 3: Divide the denominator by GCD and store as the new denominator.
Static Functions
Recall that static functions are class functions and not associated with instances of the
class (objects). In this class, the static functions GCD and LCM should accept inputs
any input pair (a and b) and return an answer based upon that input pair. As such, these
functions can be used by the programmer upon Rational Number objects or random
values for a and b.
Use the following main function to test your program. (have to use this main function)
int main() {
}
cout << endl;
// test constructors, accessors, mutators
cout << "Default Constructor: ";
RatNum r1;
cout << r1.getNum() << "/" << r1.getDen() << endl;
cout << "Single Parameter Constructor: ";
RatNum r2(2);
cout << r2.getNum() << "/" << r2.getDen() << endl;
cout << "Dual Parameter Constructor: ";
RatNum r3(1,3);
cout << r3.getNum() << "/" << r3.getDen() << endl;
cout << "Accessors / Mutators: ";
r3.setNum(3);
r3.setDen(12);
cout << r3.getNum() << "/" << r3.getDen() << endl;
// test gcd
cout << "\nGCD of the last fraction: "
<< RatNum::gcd(r3.getNum(),r3.getDen()) << endl;
cout << "GCD of 40 and 24: " << RatNum::gcd(40,24) << endl;
// test lcm
cout << "\nLCM of the last fraction:
<< RatNum::lcm (r3.getNum(),r3.getDen()) << endl;
cout << "LCM of 3 and 5: " << RatNum::lcm (3,5) << endl;
11
// test reduce
cout << "\nReducing the last fraction: ";
r3.reduce();
cout << r3.getNum() << "/" << r3.getDen() << endl;
cout << endl;
return 0;
Transcribed Image Text:1. Implement a Rational Number class with the following specifications. Data members a) numerator and denominator Functions a) Constructors: 1) default constructor 2) single parameter constructor to create numerator/1 3) dual parameter constructor to create numerator/denominator 4) Use constructor delegation across all constructors. b) Accessors and Mutators for both data members. c) Static recursive GCD function using Euclid's algorithm. d) Static LCM function for two numbers. e) Reduce function simplify a rational number. This function modifies its calling object. f) Your program should work with the supplied driver program. Notes LCM (Least Common Multiple) This function returns the smallest multiple of a and b. Step 1: Multiply a and b to find a common multiple. Step 2: Divide the common multiple by the GCD of a and b. Step 3: Return the result of Step 2. Reduce: This function reduces a fraction to simplest terms (i.e. 9/12 to 3/4). Step 1: Find the GCD of the numerator and denominator. Step 2: Divide the numerator by GCD and store as the new numerator. Step 3: Divide the denominator by GCD and store as the new denominator. Static Functions Recall that static functions are class functions and not associated with instances of the class (objects). In this class, the static functions GCD and LCM should accept inputs any input pair (a and b) and return an answer based upon that input pair. As such, these functions can be used by the programmer upon Rational Number objects or random values for a and b. Use the following main function to test your program. (have to use this main function) int main() { } cout << endl; // test constructors, accessors, mutators cout << "Default Constructor: "; RatNum r1; cout << r1.getNum() << "/" << r1.getDen() << endl; cout << "Single Parameter Constructor: "; RatNum r2(2); cout << r2.getNum() << "/" << r2.getDen() << endl; cout << "Dual Parameter Constructor: "; RatNum r3(1,3); cout << r3.getNum() << "/" << r3.getDen() << endl; cout << "Accessors / Mutators: "; r3.setNum(3); r3.setDen(12); cout << r3.getNum() << "/" << r3.getDen() << endl; // test gcd cout << "\nGCD of the last fraction: " << RatNum::gcd(r3.getNum(),r3.getDen()) << endl; cout << "GCD of 40 and 24: " << RatNum::gcd(40,24) << endl; // test lcm cout << "\nLCM of the last fraction: << RatNum::lcm (r3.getNum(),r3.getDen()) << endl; cout << "LCM of 3 and 5: " << RatNum::lcm (3,5) << endl; 11 // test reduce cout << "\nReducing the last fraction: "; r3.reduce(); cout << r3.getNum() << "/" << r3.getDen() << endl; cout << endl; return 0;
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