Out of 500 people sampled, 410 had kids. The best point estimate for pp is . The margin of error for a 99% confidence interval is Out of 500 people sampled, 465 preferred Candidate A. Based on this, estimate what proportion of the voting population prefers Candidate A with 95% confidence. If n = 500 and ˆpp^ = 0.1, construct a 90% confidence interval.

Out of 500 people sampled, 410 had kids. The best point estimate for pp is . The margin of error for a 99% confidence interval is Out of 500 people sampled, 465 preferred Candidate A. Based on this, estimate what proportion of the voting population prefers Candidate A with 95% confidence. If n = 500 and ˆpp^ = 0.1, construct a 90% confidence interval.

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

Nearly one-half of Americans ages 25 to 29 are unmarried. How large a sample is necessary to estimate the true proportion of unmarried Americans in this age group within 2 percentage points with 95% confidence?
FIND Za, FOR THE 99.50 % CONFIDENCE INTERVAL
A random sample of n1 278 people who live in a city were selected and 98 identified as a "dog person." A random sample of n2 = 109 people who live in a rural area were selected and 65 identified as a "dog person." Find the 90% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." Round answers to to 4 decimal places. < pi – p2 < Submit Question
In a survey conducted to 415 people it was found that they had walked 5000 meters on average for the past week. If s= 900, solve for the 95% confidence interval of the mean for all the respondents.
A random sample of 500 males included 215 that approved of the performance of a President. A random sample of 500 females included 185 that approved of the performance of a President. Determine each of the following parts that will lead you to construct a 95% confidence interval for the overall difference in the percentage of males and females that approve of the President's performance. group one males, gorup 2 females Calculate E, the margin of error, for a 95% level of confidence, Create the final confidence interval for the difference in percentages
In a preelection poll, a pollster finds that 442 out of 650 people polled favor Smith. Construct the 95% confidence interval for the proportion (nearest to 0.0001) of people in the whole population who favor Smith.
An epidemiologist wants to estimate the proportion of residents in her city that carry the Hepatatis A virus. It is thought that the proportion is approximately 31%. How large a sample of residents should be taken to estimate the proportion who carry the Hepatitis A virus to within 10 percentage points with 98% confidence?
You recently sent out a survey to determine if the percentage of adults who use social media has changed from 62%, which was the percentage of adults who used social media five years ago. Of the 2283 people who responded to survey, 1635 stated that they currently use social media.a) Use the data from this survey to construct a 94% confidence interval estimate of the proportion of adults who use social media. Record the result below in the form of (#,#)(#,#). Round your final answer to four decimal places.
A poll of 1070 U.S. adults found that 563 U.S. adults, or 52.617% regularly used Facebook as a news source. Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 90% level of confidence. Express all answers as percentages rounded to 2 decimal places. Do not write the percent sign. Margin of Error (as a percentage): Confidence Interval: Margin of Error (as a percentage): Confidence Interval: Now find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 95% level of confidence. Margin of Error (as a percentage): Confidence Interval: % to O increases O stays roughly the same O decreases % to Finally, find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 99% level of confidence. and the precision of our estimate O decreases O increases O stays roughly the…
You want to get a 90% confidence interval for the difference between the percentage of females with red hair compared to males with red hair. You sample 76 females and find 34 of them have red hair. You sample 65 males and find 33 have red hair. < p1−p2 <
If a 95% Confidence for the Population Proportion is (0.56, 0.78), fınd its Margin of Error.