our full (1) (2) (3) (4) 2. Knight P2.4 The figure below is a bicycle's position-vs-time graph. What is the bicycle's speed at (a) t = 5 s, (b) t = 15 s, and (c) t = 30 s? x (m) LO v (m/s) 200 150 100 50 3. Knight P2.10 The figure below shows the velocity-vs-time graph of a particle moving along the x-axis. Its initial position is co= 2.0 m at t+0=0 s. At t = 2.0 s, what are its (a) position, (b) velocity, and (c) acceleration? 6 5 4 0 0 5 10 15 20 25 30 35 40 t (s) 2 1 0 0 0.5 1 1.5 t (s) 2 2.5 3

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Help with the following questions number 2 and 3
our full
6.
(1)
(2)
(3)
(4)
2. Knight P2.4 The figure below is a bicycle's
position-vs-time graph. What is the bicycle's
speed at (a) t = 5 s, (b) t = 15 s, and (c) t = 30 s?
(w) x
200
150
100
50
6
5
4
3. Knight P2.10 The figure below shows the
velocity-vs-time graph of a particle moving along
the x-axis. Its initial position is co= 2.0 m at
t+0=0 s. At t = 2.0 s, what are its (a) position,
(b) velocity, and (c) acceleration?
(s/w) A
3
2
1
0
0
0 5 10 15 20 25 30 35 40
t (s)
0
0.5
1
Lf
1.5
t(s)
2
2.5
3
Transcribed Image Text:our full 6. (1) (2) (3) (4) 2. Knight P2.4 The figure below is a bicycle's position-vs-time graph. What is the bicycle's speed at (a) t = 5 s, (b) t = 15 s, and (c) t = 30 s? (w) x 200 150 100 50 6 5 4 3. Knight P2.10 The figure below shows the velocity-vs-time graph of a particle moving along the x-axis. Its initial position is co= 2.0 m at t+0=0 s. At t = 2.0 s, what are its (a) position, (b) velocity, and (c) acceleration? (s/w) A 3 2 1 0 0 0 5 10 15 20 25 30 35 40 t (s) 0 0.5 1 Lf 1.5 t(s) 2 2.5 3
Useful information
Kinematic equations for constant acceleration
a(t) = ao
v(t) = vo + aot
Average speed
x(t) = xo + vot +
v² =v² + 2ao Ax
Average acceleration
V =
a =
xf - xo
tf-to
Uf - vo
tf - to
Answers to one significant figure
2. -10, 0, +5 m/s
3.
1
10 m, 2 m/s, -2 m/s²
aot²
Transcribed Image Text:Useful information Kinematic equations for constant acceleration a(t) = ao v(t) = vo + aot Average speed x(t) = xo + vot + v² =v² + 2ao Ax Average acceleration V = a = xf - xo tf-to Uf - vo tf - to Answers to one significant figure 2. -10, 0, +5 m/s 3. 1 10 m, 2 m/s, -2 m/s² aot²
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