Ouestion: 06 Figure shows a circuit whose elements have the following values: E1=9 V, E2=18 V il i2 R1=R12, R2= R22 i3 The three batteries are ideal batteries. Find the magnitude and direction of the current in each of the three branches.? R1
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Q: RI a 3. Rz R3
A: Given,R1 = 1.1 kΩR2 = 3.3 kΩR3 = 1.1 kΩE = 5 V
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- 2. A 12V battery makes 1.5A of current through a 40, 30, and a 102 resistor. a. How much power does the battery supply? 1.5A AV=12V 2b. How much power is dissipated by the 402 resistor? V=OV 3Ω www 5 122 www V=? 4Ω 1.5A 2c. If the potential at the negative end of the battery is OV, what is the potential V at the star?In the following diagram, C, = 6.00 µF, C2 = 12 µF and C3= 2 µF a C2 If we apply 60 V across a and b, what is the voltage across b and d? а. 39 V b. 21 V c. 60 V d. 15 VQ6/For the network of Figure beside a. Find the currents I and 16. b. Find the voltages V₁ and V5. Find the power delivered to the 6-k-ohm resistor. E = 28 V ₁ R₁ HI. 12 k R₂ 12 k 12 R₁3 k R₂ 940 R₂ 6k0 R10.4K
- In the circuit shown in the figure, VA = VB = 10.0 V and R₁ = R₂ = R3 = R4 = R5 = 100.0 £2. Current 15 flows up through R5, and I5 = 0.0250 A. Determine the current I4 through R4. Assume the direction of positive current flow is downward through R4. 14= = Determine the voltage V₂ across R₂. V₂: = Determine the power P3 dissipated by R3. P3 = A V W www R₁ R₁ ww R₁ 4 V. B R₂ R₂9. Four resistors R₁=7.00 2, R₂=11.0 2, R3=10.0 2, and R4=8.00 2 are mounted as shown in the figure. The voltage of the battery is V = 22 Volts. What is the current in the R₂ resistor? Amps -www- R₁ R₂ -www- R3 -www- R4In the circuit shown in the figure, the potential difference VA VB = 41.0 V and the resistance R₁ = R₂ = R3 = R4 = Rs = 175 2. The arrow in the figure defines the positive direction for the flow of current IA. Determine IA.. IA = Determine the power Ps dissipated by Ps = R5. A W R₂ + + R3