In the figure, R1 = 100. Q, R2 = 50. Q, 1 = 6.0 V, 52 = 5.0 V, and 3 = 4.0 V. a) Find the current in resistor 1 and resistor 2. b) Find the potential difference in between points a and b. c) Find the power supplied by battery 2. %3D %3D %3D R2 R

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In the figure, \( R_1 = 100 \, \Omega \), \( R_2 = 50 \, \Omega \), \(\mathcal{E}_1 = 6.0 \, V\), \(\mathcal{E}_2 = 5.0 \, V\), and \(\mathcal{E}_3 = 4.0 \, V\).

a) Find the current in resistor 1 and resistor 2.
b) Find the potential difference between points a and b.
c) Find the power supplied by battery 2.

### Circuit Description

The circuit diagram contains two resistors and three batteries connected in the following way:

- Resistor \( R_1 \) is in a series with battery \(\mathcal{E}_2\).
- Resistor \( R_2 \) is connected in series with batteries \(\mathcal{E}_1\) and \(\mathcal{E}_3\).
- The arrangement is set up in such a way that the two branches combine at point a and split again at point b.

The batteries have the following orientations:
- Battery \(\mathcal{E}_1\) has the positive terminal connected towards the top.
- Battery \(\mathcal{E}_2\) has the positive terminal connected towards the left.
- Battery \(\mathcal{E}_3\) has the positive terminal connected towards the bottom.

This setup is essential for calculating the current through resistors and the potential difference, using Kirchhoff's laws and Ohm's law.
Transcribed Image Text:In the figure, \( R_1 = 100 \, \Omega \), \( R_2 = 50 \, \Omega \), \(\mathcal{E}_1 = 6.0 \, V\), \(\mathcal{E}_2 = 5.0 \, V\), and \(\mathcal{E}_3 = 4.0 \, V\). a) Find the current in resistor 1 and resistor 2. b) Find the potential difference between points a and b. c) Find the power supplied by battery 2. ### Circuit Description The circuit diagram contains two resistors and three batteries connected in the following way: - Resistor \( R_1 \) is in a series with battery \(\mathcal{E}_2\). - Resistor \( R_2 \) is connected in series with batteries \(\mathcal{E}_1\) and \(\mathcal{E}_3\). - The arrangement is set up in such a way that the two branches combine at point a and split again at point b. The batteries have the following orientations: - Battery \(\mathcal{E}_1\) has the positive terminal connected towards the top. - Battery \(\mathcal{E}_2\) has the positive terminal connected towards the left. - Battery \(\mathcal{E}_3\) has the positive terminal connected towards the bottom. This setup is essential for calculating the current through resistors and the potential difference, using Kirchhoff's laws and Ohm's law.
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