I need help with the question under the header "exercise"!!! I already solved the other 2 questions under "practice it." PRACTICE ITUse the worked example above to help you solve this problem. A proton is released from rest atx = -2.00 cm in a constant electric field with magnitude 1.50 x 103 N/C pointing in the positivex-direction.(a) Assuming an initial speed of zero, find the speed of a proton at x = 0.0300 m with a potentialenergy of –1.20 × 10-17 J. (Assume the potential energy at the point of release is zero.)1.2e5m/s(b) An electron is now fired in the same direction from the same position. Find the initial speed ofthe electron (at x = -2.00 cm) given that its speed has fallen by half when it reachesx = 0.180 m, a change in potential energy of 4.81 x 10-17 J.1.19e7v m/sEXERCISEHINTS: GETTING STARTED I I'M STUCK!The electron in part (b) travels from x = 0.180 m (where it has half the initial speed you previouslycalculated) to x = -0.300 m within the constant electric field. If there's a change in electric potentialenergy of -1.15 × 10-16 J as it goes from x = 0.180 m to x = -0.300 m, find the electron's speed atx = -0.300 m. (Note: Use the values from the Practice It section. Account for the fact that the electronmay turn around during its travel.)Vxm/s

Name: I need help with the question under the header "exercise"!!! I already
Uploaded: 2024-03-20T06:56:46.000Z
Channel: Bartleby
Description: I need help with the question under the header "exercise"!!! I already solved the other 2 questions under "practice it." PRACTICE ITUse the worked example above to help you solve this problem. A proton is released from rest atx = -2.00 cm in a consta