ou are required to use a furnace-cooled carbon Fe-Mn-0.05C alloy in a structural design that may see service temperatures as low as zero degrees Celsius. From the graph below, suggest an appropriate Mn content (in %) in the alloy.
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![Temperature, °F
50
100
150
200
-50
300
250
300
2% Mn
1% Mn
200
250
0.5% Mn
200
150
0% Mn
150
100
100
50
50
-50
-25 0 25
50 75
100
125
150
Temperature, °C
Impact energy, J
Impact energy, ft-lb](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F91a47084-2cd0-49fa-a6dd-57cd54aaaaaf%2F6a8c7ca9-b00f-4cee-9a8a-cef079f6dd1f%2Fwlthip_processed.jpeg&w=3840&q=75)
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- AE ll ll A:£0 docs.google.com/forms When a stationary mass of gas was compressed without friction at constant pressure its initial state of 0.8 m3 and 0.105 MPa was found to change to final state of 0.40 m3 and 0.105 MPa. There was a transfer of 85 kJ of heat from the gas during the process.How much did the internal energy of the gas change ? * 1 Add File Derive the law pv^y = constant * 1 Add File Вack Next Never submit passwords through Google Forms. This form was created inside L Iniversity of Al-Q1: If a calorimeter is not assumed to be adiabatic, how would one calculate the heat transfer? Guide Questions: What are the parameters to be considered and the equations to be used? What law of thermodynamics does this transfer of heat to the surroundings touch? Is an adiabatic system automatically considered as a closed system? Please help me understand by also attaching a reference/book/journal article. This would help me in my essay. Thank you.At a pressuré of 1 bar, a cylinder contains 5 m of an ideal gas. In an isothermal process, this gas is compressed until its pressure reaches 5 bar. What is the value of work done in Ki7- Select one: O a. 981.7 O b. 953,2 O c. 8047.18 O d. -804.718
- Q1. (Reading: Çengel and Boles, Thermodynamics: An Engineering Approach, 8th Ed., Pages 307-311) The amount of energy waste by a refrigerator increases by a number of malpractices. For example; opening the refrigerator door frequently will increase energy waste as the warmer air outside replaces the cool air inside. It is also not recommended to place the hot foods into the refrigerator before cooling them to the room temperature. Imagine a typical household refrigerator with an internal temperature of 4 °C. The refrigerator has a coefficient of performance of 1.4. The internal dimensions of this refrigerator are 186 cm (height) x 84 cm (width) x 75 cm (depth). The half of the refrigerator volume is used for storing food items. The air filling the other half of the refrigator volume contains 0.004 kg moisture/kg air on average. While the moisture content of the air in the kitchen is 0.01 kg/kg air, the temperature and pressure in the kitchen are 23°C and 97 kPa, respectively. Assuming…M: Constarm h=chang Q2. Heat cannot be zero in closed system (True/False). ( F cee Q1. Work cannot be zero in closed system (True/False) Q3. First law of thermodynamics is not based on the law of conservation of energy (True/False), Q4. The change in the total energy of the closed system is -Q5. The sum of the'energiesCarried by the mass in open system is.Mashalase Emi =Eme Q-w=AH fluichProleabie.haT ehange with Time Q6. The general form of first law of thermodynamics for open system.. Q7. Un steady state flow process is defined as. internal+ Q8. Enthalpy is defined sum of kinetic and flow energy (True False), 09. Cyclic process is defined as.wha.h.ystem start from initial state trour, L diffrent Processes and .e.k... Q10. Internal energy is considered in open system (True/False)İI have some things that need clarification based on the answer provided to this question. Firstly, the h1 value came out as 154.99 kJ/Kg for me not 153.318. Also, the values taken from the steam table for Vf and Vg for 5 degrees celcius and 6 degrees are different from what is on the steam table, I have attached a picture for this. For 5 degrees on the steam table it shows Vf as 0.00100008 and Vg as 147.011 and for 6 degrees it shows Vf as 0.00100011 and Vg as 137.633. Please clarify this and reply as soon as possible. Thanks
- 1. A certain ideal gas Y has molecular weight of 25 g/mol and specific heat ratio of 3. Initially, Y has pressure of 200kPa and volume of 2m3. The volume was doubled during heat transfer. Find the heat transfer if it underwent a process described by ( a. n=1 b. n=Cp/Cv C. n=2The left side of this equation tells how much energy Q the cylinder gives to the water while it cools. The right side of this equation tells how much energy Q the water and aluminum cup absorb from the cylinder to warm up. Because it is the same energy, they are equal. What is known in this equation? Mcyl 411.7 g, malum 46.5 g, malum+water = 175 g Can you find: mwater =? g Twater = Talum = 20°C (water and cup of room temperature) 90°C, T; = 35°C (hot cylinder and cool "cylinder+cup+water" temperatures) Tcyl kCal Calum = 0.22, Cwater 1 (specific heat of water and aluminum, measured in units kg-°C What are we looking for is Ccul - How we find it? Plug all the numbers into the equation (1), Ccul will be one unknown which you can calculate from the equation. Important, convert all the masses from grams to kilograms! After you find Ccyl, compare it to known value for the copper 0.093(our cylinder is made out of copper). |Ceyl -0.093| % : · 100% 0.0931%AV l1. li, a O lir. lin. Oよイ0 1r 10 i docs.google.com/forms/d/e مطلوب Untitled Section F1 F2 a F3 F4 E B Consider the following values: - FS a - 25 m; b - 5 m; a - 25 m; d - 5 m; F1 - 6 kN; F2 - 14 kN; P3 - 7 kN; F4 - 2 kN; P5 - 20 kN; a = 30°, e= 60°, B= 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 155.8 kN.m b) 122.7 KN.m )-261.4 KN.m d) 212.9 kN.m e) 294.1 KN.m 1- 167.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 266.8 kN.m b) 25.7 kN.m c)-416.3 KN.m đ) 98.9 KN.m e) 189.4 kN.m D 324.2 KN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) - 846.7 KN.m b) 571I EN.m )-4313KN.m d) 2749 KNm e)-174.1 EN.am f) 3553 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) - 117.8 EN.m b) 142.7 KN.m )- 360.7 KN.m d) 286.9 KN.m e)- 417.1 KN.m H 300.1 kN.m 5] What is the moment of the force F2 about point E? a) 111.7 kN.m b)…
- Q1. The following data is obtained during geothermal drilling operation. Rock density = 1550 kg/m ³, heat capacity of the rock = 0.00163 J/kg K, temperature difference = 80 K. How much will be the thermal heat content of the rock at the geothermal site? Discuss about geothermal gradients their importance in energy exploration. Do you think utilization of geothermal energy worldwide is increasing yearly? Justify your answer. Do you think the geothermal energy available in this site can be used for a metal melting industry?Which of the following is intensive property heat: work, internal energy, specific heat, heat capacity, pressure35 kg of certain gas is contained within the piston- cylinder assembly. THE GAS undergoes a process which is pv=constant.The given conditions as follows; p1=6bars,v1=0.2cubic meters,v2=0.4 cubits meters,the change of internal energy=10.5kj/kg.(hints:kE=PE=0) A)Find P2 in bars B) Find the work in kj for n=1.0 C) Find the net heat transfer Q for the process in kj
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