||| O PRINCIPLES OF ORGANIC CHEMISTRY Deducing oxidation state from a Lewis structure What is the most oxidized of the labeled carbon atoms in this molecule? What is the most reduced? OH O O H O a H-C b C H с C d e C -C H OH Enter the label of the most oxidized labeled C atom Enter the label of the most reduced labeled C atom 0 0 X
||| O PRINCIPLES OF ORGANIC CHEMISTRY Deducing oxidation state from a Lewis structure What is the most oxidized of the labeled carbon atoms in this molecule? What is the most reduced? OH O O H O a H-C b C H с C d e C -C H OH Enter the label of the most oxidized labeled C atom Enter the label of the most reduced labeled C atom 0 0 X
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Title: Deducing Oxidation State from a Lewis Structure**
**Section: Principles of Organic Chemistry**
---
**Question:**
What is the most oxidized of the labeled carbon atoms in this molecule? What is the most reduced?
**Chemical Structure Diagram:**
The molecule is presented with labeled carbon atoms in a chain. The oxidation levels of these carbons differ due to their bonding with oxygen and hydrogen atoms.
- **Oxygen atoms (O)** are double-bonded to some carbons and hydroxyl groups (-OH) are attached to others.
- Carbons are identified by letters, e.g., (a), (b), etc.
- Structure:
- Carbon (a) is bonded with an -OH group.
- Carbon (b) is bonded with a double-bonded oxygen (C=O).
- Carbon (c) is in a similar environment as carbon (a).
- Carbon (d) is bonded with another C=O.
- Carbon (e) has an -OH group attached.
**Inputs:**
1. Enter the label of the most oxidized labeled C atom: [Input Box]
2. Enter the label of the most reduced labeled C atom: [Input Box]
**Buttons:**
- **Explanation**
- **Check**
**Additional Information:**
This is an interactive exercise for students to apply their understanding of oxidation states by analyzing the Lewis structure of organic molecules.
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Transcribed Image Text:**Title: Deducing Oxidation State from a Lewis Structure**
**Section: Principles of Organic Chemistry**
---
**Question:**
What is the most oxidized of the labeled carbon atoms in this molecule? What is the most reduced?
**Chemical Structure Diagram:**
The molecule is presented with labeled carbon atoms in a chain. The oxidation levels of these carbons differ due to their bonding with oxygen and hydrogen atoms.
- **Oxygen atoms (O)** are double-bonded to some carbons and hydroxyl groups (-OH) are attached to others.
- Carbons are identified by letters, e.g., (a), (b), etc.
- Structure:
- Carbon (a) is bonded with an -OH group.
- Carbon (b) is bonded with a double-bonded oxygen (C=O).
- Carbon (c) is in a similar environment as carbon (a).
- Carbon (d) is bonded with another C=O.
- Carbon (e) has an -OH group attached.
**Inputs:**
1. Enter the label of the most oxidized labeled C atom: [Input Box]
2. Enter the label of the most reduced labeled C atom: [Input Box]
**Buttons:**
- **Explanation**
- **Check**
**Additional Information:**
This is an interactive exercise for students to apply their understanding of oxidation states by analyzing the Lewis structure of organic molecules.
© 2023 McGraw Hill LLC. All Rights Reserved.
Expert Solution
Step 1: Define Oxidation State
Oxidation number is the hypothetical charge developed on an atom when it is separated from other atoms in a bond.
Most oxidized carbon would be the one which would be having highest oxidation state while most reduced carbon would be the one which would be having lowest oxidation state.
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