ormal distribution has a mean of 104 and a standard deviation of 10. Find the z-score for a data value of 80. Round to two decimal places
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- Scores had a Mean of 82 and a Standard Deviation of 5 0. Find a z score for x = 81 and x = 68 Z- score for 81 -0.2 -2.8 Z- score for 68 1. Find the percent of scores that were above 86. Z score for 86 Table score for 86Assume that women have heights that are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. The middle 50% of the heights are between what two values? Round to one decimal place. 60.3 inches and 66.9 inches 61.9 inches and 65.3 inches 62.3 inches and 64.9 inches 63.1 inches and 64.1 inchesA distribution of values is normal with a mean of 202 and a standard deviation of 91.5.Find P75, which is the score separating the bottom 75% from the top 25%.P75 =
- Length of snowboards in a boardshop are normally distributed with a mean of 150.4 cm and a standard deviation of 0.7 cm. The figure below shows the distribution of the length of snowboards in a boardshop. Calculate the shaded area under the curve. Express your answer in decimal form with at least two decimal place accuracy. 149.7 151.8 The Length of Snowboards in a BoardshopA normal distribution has a mean of 85 and a standard deviation of 6. Find the z-score for a data value of 92. places Round to two decimalA variable has a mean of 100 and a standard deviation of 16. Four observations of this variable have a mean of 108 and a sample standard deviation of 12. Determine the observed value of the a. standardized version of x. b. studentized version of x.
- Interpret the Z score for a student who scored an 91 on an exam that had a mean of 86 and a standard deviation of 5. One mean above the standard deviation One standard deviation above the mean One standard deviation below the mean One mean below the standard deviationIQ scores are normally distributed with a mean of 100 and standard deviation 16. Calculate the z-score for an IQ of 76. Include one decimal place in your answer. Add your answerThe distribution of heights in a population of women is approximately normal. Sixteen percent of the women have heights less than 62 inches. About 97.5% of the women have heights less than 71 inches. Use the empirical rule to estimate the mean and standard deviation of the heights in this population. Mean: K inches Standard Deviation: inches
- Adult men have an average height of 69.0 inches with a standard deviation of 2.8 inches. Find the height of a man with a z-score of 0.07. Round your answer to one decimal place. inchesA set of population data has a mean of 586 and a standard deviation of 54.8. Calculate the z-score for a data point that has the value 607.9. Round your answer off to 2 decimal places.A normal distribution has a mean of 15 and a standard deviation of 2. Find the value that corresponds to the 75th percentile. Round your answer to two decimal places.
