仚 |凸https://ng.cengage.com/static/nb/ui/evo/index.html?O ☆ | INDTAP stions 2. a search this course Use the References to access important values if needed for this question. The reaction C4Hsg2C2Hs(g) is first order. In an experiment, the rate constant is determined to be 9.84x10-4 s-1 at 461°C. (a) Calculate the half-life of the reaction at 461°C based on this experiment. (b) If the initial partial pressure of C4lHls in a container at 461°C is 4.00 atm, how long will it take to fall to 0.500 atm? Back Autosaved at 9:29 AM Next Type here to search enovo

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仚 |凸https://ng.cengage.com/static/nb/ui/evo/index.html?O ☆ |
INDTAP
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2.
a search this course
Use the References to access important values if needed for this question.
The reaction C4Hsg2C2Hs(g) is first order. In an experiment, the rate
constant is determined to be 9.84x10-4 s-1 at 461°C.
(a) Calculate the half-life of the reaction at 461°C based on this experiment.
(b) If the initial partial pressure of C4lHls in a container at 461°C is 4.00 atm, how
long will it take to fall to 0.500 atm?
Back
Autosaved at 9:29 AM
Next
Type here to search
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Transcribed Image Text:仚 |凸https://ng.cengage.com/static/nb/ui/evo/index.html?O ☆ | INDTAP stions 2. a search this course Use the References to access important values if needed for this question. The reaction C4Hsg2C2Hs(g) is first order. In an experiment, the rate constant is determined to be 9.84x10-4 s-1 at 461°C. (a) Calculate the half-life of the reaction at 461°C based on this experiment. (b) If the initial partial pressure of C4lHls in a container at 461°C is 4.00 atm, how long will it take to fall to 0.500 atm? Back Autosaved at 9:29 AM Next Type here to search enovo
Expert Solution
Step 1

For a first order reaction, the half-life of the reaction is found using the below formula.

Chemistry homework question answer, Step 1, Image 1
Step 2

(a)

Determine the half-life for the given reaction from the given value of rate constant.

Chemistry homework question answer, Step 2, Image 1
Step 3

(b)

For the first order reaction,

Chemistry homework question answer, Step 3, Image 1
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