or the reaction: Bro3 (aq) + 5Br (aq) + 8H*(aq) → 3Br2(f) + H2O(8) The initial rate of the reaction has been measured at the reactant concer how: Trial [BrO3] (mol/L) [H] [Br ] Initial rate (mol/L) (mol/L) (mol/L-s) 8.0 16 0.10 0.10 0.10 0.20 0.10 0.10 0.10 0.20 0.10 16 0.10 0.10 0.20 32 234
or the reaction: Bro3 (aq) + 5Br (aq) + 8H*(aq) → 3Br2(f) + H2O(8) The initial rate of the reaction has been measured at the reactant concer how: Trial [BrO3] (mol/L) [H] [Br ] Initial rate (mol/L) (mol/L) (mol/L-s) 8.0 16 0.10 0.10 0.10 0.20 0.10 0.10 0.10 0.20 0.10 16 0.10 0.10 0.20 32 234
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![For the reaction: Bro3 (aq) + 5Br (aq) + 8H*(aq) → 3Br2(f) + H20(6)
The initial rate of the reaction has been measured at the reactant concentrations
show:
Trial [BrO,]
[H']
(mol/L) (mol/L)
0.10
[Br]
(mol/L)
Initial rate
(mol/L-s)
1
0.10
0.10
8.0
0.20
0.10
0.10
16
0.10
0.20
0.10
16
0.10
0.10
0.20
32
The rate law expression will be:
234](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe144ef3b-a792-4526-b677-ad6ee25347f4%2F96da7338-f549-475f-ae54-d90e698a92c9%2F3j05k05_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For the reaction: Bro3 (aq) + 5Br (aq) + 8H*(aq) → 3Br2(f) + H20(6)
The initial rate of the reaction has been measured at the reactant concentrations
show:
Trial [BrO,]
[H']
(mol/L) (mol/L)
0.10
[Br]
(mol/L)
Initial rate
(mol/L-s)
1
0.10
0.10
8.0
0.20
0.10
0.10
16
0.10
0.20
0.10
16
0.10
0.10
0.20
32
The rate law expression will be:
234
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