138 Experiment 3 Kinetic Study: The lodine Clock Reaction 2. The reaction H2 (g) + 2 NO (g) → N2O (g) + H2O (g) is studied at a certain tempera- ture by determining the rate of reaction at reactant concentrations. The results are as follows. Concentration (M) Rate [NO] [H]] (M/s) (i) 0.25 0.10 0.126 (ii) 0.50 0.10 0.504 (iii) 0.50 0.20 1.03 The rate law is written as Rate k [NO]* [H2]. The exponents x and y represent the order with respect to NO and H2, respectively. Calculate the value of x and y from the data provided. 3. The decomposition of N,O5 in carbon tetrachloride has been studied: 2 N2O5 (g) → 2 N,O4 (g) + O2 (g) The concentration of N,O5 is measured every 400 seconds. The data are tabulated below. [N,O5] (M) time Δt A[N,Os] (M) Rate = -A[N,O;]/At (M/s) %3D (s) (s) 0.0 1.40 400.0 1.10 800.0 0.87 1200.0 0.68 a) Fill the blanks in the table. Note that the last column is the average rate of reaction. b) Briefly explain why the rates are decreasing.
138 Experiment 3 Kinetic Study: The lodine Clock Reaction 2. The reaction H2 (g) + 2 NO (g) → N2O (g) + H2O (g) is studied at a certain tempera- ture by determining the rate of reaction at reactant concentrations. The results are as follows. Concentration (M) Rate [NO] [H]] (M/s) (i) 0.25 0.10 0.126 (ii) 0.50 0.10 0.504 (iii) 0.50 0.20 1.03 The rate law is written as Rate k [NO]* [H2]. The exponents x and y represent the order with respect to NO and H2, respectively. Calculate the value of x and y from the data provided. 3. The decomposition of N,O5 in carbon tetrachloride has been studied: 2 N2O5 (g) → 2 N,O4 (g) + O2 (g) The concentration of N,O5 is measured every 400 seconds. The data are tabulated below. [N,O5] (M) time Δt A[N,Os] (M) Rate = -A[N,O;]/At (M/s) %3D (s) (s) 0.0 1.40 400.0 1.10 800.0 0.87 1200.0 0.68 a) Fill the blanks in the table. Note that the last column is the average rate of reaction. b) Briefly explain why the rates are decreasing.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![138
Experiment 3 Kinetic Study: The lodine Clock Reaction
2. The reaction H2 (g) + 2 NO (g) → N2O (g) + H2O (g) is studied at a certain tempera-
ture by determining the rate of reaction at reactant concentrations. The results are as
follows.
Concentration (M)
Rate
[NO]
[H]]
(M/s)
(i)
0.25
0.10
0.126
(ii)
0.50
0.10
0.504
(iii)
0.50
0.20
1.03
The rate law is written as Rate
k [NO]* [H2]. The exponents x and y represent the
order with respect to NO and H2, respectively. Calculate the value of x and y from the
data provided.
3. The decomposition of N,O5 in carbon tetrachloride has been studied:
2 N2O5 (g) → 2 N,O4 (g) + O2 (g)
The concentration of N,O5 is measured every 400 seconds. The data are tabulated below.
[N,O5]
(M)
time
Δt
A[N,Os]
(M)
Rate = -A[N,O;]/At
(M/s)
%3D
(s)
(s)
0.0
1.40
400.0
1.10
800.0
0.87
1200.0
0.68
a) Fill the blanks in the table. Note that the last column is the average rate of reaction.
b) Briefly explain why the rates are decreasing.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdce7689d-4520-4a5f-90cf-3f573cfd3075%2F978d0877-e9c3-4889-9889-1420a7ae3429%2Fyxornwtd.jpeg&w=3840&q=75)
Transcribed Image Text:138
Experiment 3 Kinetic Study: The lodine Clock Reaction
2. The reaction H2 (g) + 2 NO (g) → N2O (g) + H2O (g) is studied at a certain tempera-
ture by determining the rate of reaction at reactant concentrations. The results are as
follows.
Concentration (M)
Rate
[NO]
[H]]
(M/s)
(i)
0.25
0.10
0.126
(ii)
0.50
0.10
0.504
(iii)
0.50
0.20
1.03
The rate law is written as Rate
k [NO]* [H2]. The exponents x and y represent the
order with respect to NO and H2, respectively. Calculate the value of x and y from the
data provided.
3. The decomposition of N,O5 in carbon tetrachloride has been studied:
2 N2O5 (g) → 2 N,O4 (g) + O2 (g)
The concentration of N,O5 is measured every 400 seconds. The data are tabulated below.
[N,O5]
(M)
time
Δt
A[N,Os]
(M)
Rate = -A[N,O;]/At
(M/s)
%3D
(s)
(s)
0.0
1.40
400.0
1.10
800.0
0.87
1200.0
0.68
a) Fill the blanks in the table. Note that the last column is the average rate of reaction.
b) Briefly explain why the rates are decreasing.
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