Derive the weak form of the problem. Pay attention to the treatment of boundary conditions and body loads. yالتاناتيThe boundary conditions areРLThe strong form of governing equation for a simply supported beam under a distributed loadp, shown in the figure above, is as followsd²v M(x)dx²X0EIwhere v is the deflection in y direction, E is Young's modulus, I is the second moment ofinertia, M(x) is the internal bending moment and is given bypx(L-x)M(x) =2v(0) = 0v(L)=0

Answered: Image /qna-images/answer/ea28a53d-ff7c-4bb6-8797-9b719e104a77.jpg

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Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Show your complete solution with dimensional analysis. 1-2. 5.5. Plot the shear and bending-moment diagrams for the beam shown if P = 0, wi = 0, and w2 10 lb/in. W2 *--30*- 40"- 30- - 30- 100* – IR, PROBS. 5.5 and 5.6. 5.6. Plot the shear and bending-moment diagrams for the beam shown if P = 2,000 lb, wi = 10 lb/in., and wz = 20 lb/in.
In the figure below, a ball is thrown up onto a roof, landing 4.14 s later at height h = 24.5 m above the release level. The ball's path just before landing is angled at @ = 60.0° with the roof. (Let the positive x direction be to the right, and the positive y direction be upward.) (a) Find the horizontal distance d it travels. (Hint: One way is to reverse the motion, as if on video.) (b) What is the magnitude of the ball's initial velocity? (c) What is the angle (relative to the horizontal) of the ball's initial velocity?
Friction Example, 1 A 3kg block starts from rest at the top of 30o incline and slides with a = 1.78 m/s2. Find Sne and (a) the coefficient of kinetic friction between the block and the plane (b) the friction force acting on the block mg sin@ mg cos e Solu on mg Yo 0.368
K = 1.4*10-4
Cornering force and drag force on tires. Consider a tire that has lateral force behavior like the one in the following figure. Assuming that the drift angle is 4 degrees and the normal force F = 5000N, calculate the cornering and drag forces on the tire.
I need the answer at 20 minute
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3) Calculations for the red dog food can rolling down the slope in the Rube Goldberg design are as follows (we will name it Step 1): DO Step 1 (calculations are given): Coefficient of friction → μ = 0.14 Mass of the object → m = 368 gm = 0.368kg Initial height of the object (red can on top of books) → h=8.89, cm = 0.0889 m Slope of the file folder → 0 = 14° Travelling Distance by the object = 11.5 inch = 0.292 m And length that the object will travel = h/sin 0 = 0.0889/ sin14° = 0.367 m So, the radius of the object → R = 0.367 -0.292 = 0.075 m Initial Velocity of red can → u=0 Velocity and Force Calculations for Step 1: -From total mechanical energy conservation: → Initial mechanical energy = final mechanical energy → mg - In case of pure rolling, the velocity of the center of mass: →→V=Ro=0.075 x 14.28 = 1.07 m/s. -Hence the change in force acting on the object for the travel: →F=mgsine = 0.368 x 9.81 × sin14° =0.89 N Step 2: The Selective Step (Step 2) in this design and for the…
1) Calculations for the red dog food can rolling down the slope in the Rube Goldberg design are as follows (we will name it Step 1): Step 1 (calculations are given): Coefficient of friction → μ = 0.14 Mass of the object-m-368 gm = 0.368kg Initial height of the object (red can on top of books) → h=8.89, cm = 0.0889 m Slope of the file folder → 9 = 14° Travelling Distance by the object = 11.5 inch = 0.292 m And length that the object will travel=h/sin 0 = 0.0889/ sin14° = 0.367 m So, the radius of the object →R=0.367 -0.292 = 0.075 m Initial Velocity of red can → u=0 Velocity and Force Calculations for Step 1: -From total mechanical energy conservation: → Initial mechanical energy = final mechanical energy → mg - In case of pure rolling, the velocity of the center of mass: →V=Ro= 0.075 x 14.28 = 1.07 m/s. -Hence the change in force acting on the object for the travel: →F=mgsin0 = 0.368 × 9.81 × sin14° =0.89 N Step 2: The Selective Step (Step 2) in this design and for the questions below…
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A person is pushing on a uniform block of wood as shown in the figure and parameter table. The block of wood has mass 140 kg and a coefficient of static friction of 4, w = 0.3. Assume the person only exerts a horizonatal force on the block of wood, and their shoes have a coefficient of static friction Hs,p = 0.4. What is the minimum mass the person needs to be able to move the block? Also, what is the maximum value of 4s,w that the wood could have and still slide instead of tip if pushed at the same location? L3 value units parameter L L2 La 1.7 m 1.1 2.8 Minimum mass of person = kg Maximum value of us,w before block would tip =
a box with a mass 20kg its been pull with a force constant P=W of the box was in constant repose what is the velocity after the box reach a distance of 2m, with a coheficient mk=0.2

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