Answered: | = 2m/s y A Vl = 4m/s A А B |Ve = 0 B)… | bartleby

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Two disks on the friction-free air table with a mass of Ma=0.5kg and Mb=0.3kg are colliding flexibly as shown in the figure. After collision, find the speed of disk B and the disks scattering angle (α and β angles).

sin a + cos a = 1
sin 8+ cos B = 1
cos(a + B) = cosa · cosß - sina · sinß
cos(a - B) = cosa · cosß + sina · sinß
sin(a + B) = sina · cosß + cosa · sinß
sin(a – ß) = sina · cosß – cosa · sinß

VA| = 2m/s
y
A
mA
VA| = 4m/s
mB
A
B
V = 0
В
Bs

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