A particle P of mass m = 0.56 kg is released from rest at a point h = 7 m above the surface of a liquid in a container. P falls through the air into the liquid. Assume there is no air resistance and there is no instantaneous change in speed of P as it enters the liquid. When P is at a distance of d = 0.71 m below the surface of the liquid, P's speed is v = 4.9 m/s. The only force acting on P due to the liquid is a constant resistance to motion of magnitude R N. Find the following: v1: The speed (in m/s) of P the moment just before it strikes the surface of the fluid. a1: The magnitude of the deceleration (in m/s2) of P while it is falling through the liquid. R: The magnitude of the resistance force (in N). The depth of the liquid in the container is dp = 3.9 m. P is taken from the container and attached to one end of a light inextensible string. P is placed at the bottom of the container and then pulled vertical upwards with a constant acceleration, a2. The resistance force to motion R N continues to act. The particle reaches the surface t = 7 s after leaving the bottom. Calculate: a2: The magnitude of the acceleration (in m/s2) of P as it is pulled upwards. T: The tension (in N) in the string.
A particle P of mass m = 0.56 kg is released from rest at a point h = 7 m above the surface of a liquid in a container. P falls through the air into the liquid. Assume there is no air resistance and there is no instantaneous change in speed of P as it enters the liquid. When P is at a distance of d = 0.71 m below the surface of the liquid, P's speed is v = 4.9 m/s. The only force acting on P due to the liquid is a constant resistance to motion of magnitude R N. Find the following:
v1: The speed (in m/s) of P the moment just before it strikes the surface of the fluid.
a1: The magnitude of the deceleration (in m/s2) of P while it is falling through the liquid.
R: The magnitude of the resistance force (in N).
The depth of the liquid in the container is dp = 3.9 m. P is taken from the container and attached to one end of a light inextensible string. P is placed at the bottom of the container and then pulled vertical upwards with a constant acceleration, a2. The resistance force to motion R N continues to act. The particle reaches the surface t = 7 s after leaving the bottom. Calculate:
a2: The magnitude of the acceleration (in m/s2) of P as it is pulled upwards.
T: The tension (in N) in the string.
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