Option 1Option 2Option 3P(x)P(x)P(x)хх0.010.10.250.010.310.460.970.40.0430.010.130.24Using the only valid probability distribution option shown above, compute thestandard deviation.Round to four (4)decimal places.8O7 23

Properties of probability: The probability value lies between 0 and 1 (inclusive). That is 0 ≤ P(x)…

Answered: Option 1 Option 2 Option 3 P(x) P(x)…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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x P(x) 0 0.12 1 0.08 2 0.08 3 0.08 4 0.14 5 0.1 6 0.14 7 0.26 Find the variance of this probability distribution.Give your answer to at least 2 decimal places
variable with the following probability distribution. Value x of X P=Xx -20 0.10 -10 0.15 0 0.45 10 0.25 20 0.05 Complete the following. (If necessary, consult a list of formulas.) (a) Find the expectation EX of X . ? =EX (b) Find the variance Var X of X .? =VarX
Find the mean, variance, and standard deviation of the random variable having the probability distribution given in the following table. (Round your answers to four decimal places.) Random variable, x -8 -7 -6 -5 -4 P(X = x) 0.14 0.16 0.42 0.12 0.16 mean variance standard deviation
Find the standard deviation of the random variable X with the given probability distribution. * 1 P(x) 0.34 0.25 0.20 2.
xx P(x)P(x) 0 0.15 1 0.05 2 0.2 3 0.6 Find the standard deviation of this probability distribution. Give your answer to at least 2 decimal places
Determine the required value of the missing probability to make the distribution a discrete probability distribution. Р(x) 3 0.24 4 ? 0.22 0.26 P(4) = (Type an integer or a decimal.)
............
Compute the mean and standard deviation of the random variable with the given discrete probability distribution. x Px −5 0.11 1 0.26 4 0.23 6 0.28 8 0.12 (a) Find the mean. Round the answer to three decimal places, if necessary. (b) Find the standard deviation. Round the answer to three decimal places, if necessary.
Which of the given distributions represents a probability distribution? (i) X 1 2 3 4 O only (ii) O only (iii) O only (i) P(x) O (only (i) and (ii) 0.22 O Only (ii) and (iii) 0.36 0.29 0.16 (ii) X 5 6 7 8 P(x) 0.25 -0.22 0.41 0.12 (iii)

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Option 1 Option 2 Option 3 P(x) P(x) P(x) х х 0.01 0.1 0.25 0.01 0.3 1 0.46 0.97 0.4 0.04 3 0.01 0.1 3 0.24 Using the only valid probability distribution option shown above, compute the standard deviation. Round to four (4) decimal places. 8O7 23