Use the probability distribution t complete parts (a) and (b) below. The number of defects per 1000 machine parts inspected Defects 3 4 0 0.267 1 0.296 2 0.240 Probability 0.147 0.037 (a) Find the mean, variance, and standard deviation of the probability distribution. The mean is (Round to one decimal place as needed.) The variance is (Round to one decimal place as needed.) The standard deviation is. (Round to one decimal place as needed.) (b) Interpret the results. 5 0.013 The mean is, so the average batch of 1000 machine parts has (Round to one decimal place as needed.) D 1 or 2 defects. no defects. The standard deviation is at least 2 defects. ,so the typical number of defects in a batch of 1000

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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Use the probability distribution to complete parts (a) and (b) below.
The number of defects per 1000 machine parts inspected
Defects
0
0.267
1
0.296
2
0.240
3
0.147
Probability
The variance is.
(Round to one decimal place as needed.)
4
0.037
(a) Find the mean, variance, and standard deviation of the probability distribution.
The mean is
(Round to one decimal place as needed.)
The standard deviation is
(Round to one decimal place as needed.)
(b) Interpret the results.
5
0.013
The mean is so the average batch of 1000 machine parts has
(Round to one decimal place as needed.)
1 or 2 defects.
no defects.
0
The standard deviation is
at least 2 defects.
so the typical number of defects in a batch of 1000
Transcribed Image Text:Use the probability distribution to complete parts (a) and (b) below. The number of defects per 1000 machine parts inspected Defects 0 0.267 1 0.296 2 0.240 3 0.147 Probability The variance is. (Round to one decimal place as needed.) 4 0.037 (a) Find the mean, variance, and standard deviation of the probability distribution. The mean is (Round to one decimal place as needed.) The standard deviation is (Round to one decimal place as needed.) (b) Interpret the results. 5 0.013 The mean is so the average batch of 1000 machine parts has (Round to one decimal place as needed.) 1 or 2 defects. no defects. 0 The standard deviation is at least 2 defects. so the typical number of defects in a batch of 1000
Use the probability distribution to complete parts (a) and (b) below.
The number of defects per 1000 machine parts inspected
Defects
3
0
0.267
1
0.296
2
0.240
Probability
0.147
The variance is
(Round to one decimal place as needed.)
4
0.037
(a) Find the mean, variance, and standard deviation of the probability distribution.
The mean is
(Round to one decimal place as needed.)
The standard deviation is
(Round to one decimal place as needed.)
(b) Interpret the results.
5
0.013
The mean is so the average batch of 1000 machine parts has
(Round to one decimal place as needed.)
0
The standard deviation is
■
-
ī
so the typical number of defects in a batch of 1000
L
G
()
Moro
deviates from the mean by about 1 defect.
does not deviate from the mean.
deviates from the mean by more than 2 defects.
deviates from the mean by about 2 defects.
Transcribed Image Text:Use the probability distribution to complete parts (a) and (b) below. The number of defects per 1000 machine parts inspected Defects 3 0 0.267 1 0.296 2 0.240 Probability 0.147 The variance is (Round to one decimal place as needed.) 4 0.037 (a) Find the mean, variance, and standard deviation of the probability distribution. The mean is (Round to one decimal place as needed.) The standard deviation is (Round to one decimal place as needed.) (b) Interpret the results. 5 0.013 The mean is so the average batch of 1000 machine parts has (Round to one decimal place as needed.) 0 The standard deviation is ■ - ī so the typical number of defects in a batch of 1000 L G () Moro deviates from the mean by about 1 defect. does not deviate from the mean. deviates from the mean by more than 2 defects. deviates from the mean by about 2 defects.
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