(Optimization) The length of the longest ladder that can negotiate the corner depicted in Figure 2 can be determined by computing the value of that minimizes the following function: L (theta) = w1/sin (theta) + w2/sin (pi \[Minus] alpha \[Minus] theta) For the case where w1 = w2 = 2 m, use a numerical method to develop a plot of L versus a range of alpha's from 45 to 135 degrees. 102 C Show Transcribed Text α I have this solution in Mathematica. What I need is to use something else instead of FindMinimum (Or other automatic methods). Probably, i should use optimization: Golden-section search or Parabolic interpolation. Any help? Thanks! Plot[First@ FindMinimum [[2/Sin[th] + 2/Sin[Pi - (alpha Degree) -th], 0th Pi alpha Degree), th], (alpha, 45, 135), PlotRange -> {0, Automatic}] 10 8 80 80 100 120 Show Transcribed Text
(Optimization) The length of the longest ladder that can negotiate the corner depicted in Figure 2 can be determined by computing the value of that minimizes the following function: L (theta) = w1/sin (theta) + w2/sin (pi \[Minus] alpha \[Minus] theta) For the case where w1 = w2 = 2 m, use a numerical method to develop a plot of L versus a range of alpha's from 45 to 135 degrees. 102 C Show Transcribed Text α I have this solution in Mathematica. What I need is to use something else instead of FindMinimum (Or other automatic methods). Probably, i should use optimization: Golden-section search or Parabolic interpolation. Any help? Thanks! Plot[First@ FindMinimum [[2/Sin[th] + 2/Sin[Pi - (alpha Degree) -th], 0th Pi alpha Degree), th], (alpha, 45, 135), PlotRange -> {0, Automatic}] 10 8 80 80 100 120 Show Transcribed Text
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![(Optimization) The length of the longest ladder that can negotiate the corner depicted in Figure 2 can be determined by computing
the value of that minimizes the following function:
L (theta) = w1/sin (theta) + w2/sin (pi \[Minus] alpha \[Minus] theta)
For the case where w1 = w2 = 2 m, use a numerical method to develop a plot of L versus a range of alpha's from 45 to 135 degrees.
102
C
Show Transcribed Text
α](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb392b50f-f9c7-48cd-a379-2972074f7ee7%2F7cf6197a-cba8-4a0a-b020-530abd67b8ac%2Fxus9tog_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(Optimization) The length of the longest ladder that can negotiate the corner depicted in Figure 2 can be determined by computing
the value of that minimizes the following function:
L (theta) = w1/sin (theta) + w2/sin (pi \[Minus] alpha \[Minus] theta)
For the case where w1 = w2 = 2 m, use a numerical method to develop a plot of L versus a range of alpha's from 45 to 135 degrees.
102
C
Show Transcribed Text
α
![I have this solution in Mathematica. What I need is to use something else instead of FindMinimum (Or other automatic methods).
Probably, i should use optimization: Golden-section search or Parabolic interpolation. Any help? Thanks!
Plot[First@
FindMinimum [[2/Sin[th] + 2/Sin[Pi - (alpha Degree) -th],
0th Pi alpha Degree), th],
(alpha, 45, 135),
PlotRange -> {0, Automatic}]
10
8
80
80
100
120
Show Transcribed Text](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb392b50f-f9c7-48cd-a379-2972074f7ee7%2F7cf6197a-cba8-4a0a-b020-530abd67b8ac%2Flnccm3j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:I have this solution in Mathematica. What I need is to use something else instead of FindMinimum (Or other automatic methods).
Probably, i should use optimization: Golden-section search or Parabolic interpolation. Any help? Thanks!
Plot[First@
FindMinimum [[2/Sin[th] + 2/Sin[Pi - (alpha Degree) -th],
0th Pi alpha Degree), th],
(alpha, 45, 135),
PlotRange -> {0, Automatic}]
10
8
80
80
100
120
Show Transcribed Text
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