oof. Assume that n is an odd integer. Then n 2k + 1 for some integer k. Then %3D 7n - 5 = 7(2k+1) - 5 = 14k + 7-5 = 14k + 2 = 2(7k + 1). Since 7k + 1 is an integer, 7n- 5 is even. q.e.d.
oof. Assume that n is an odd integer. Then n 2k + 1 for some integer k. Then %3D 7n - 5 = 7(2k+1) - 5 = 14k + 7-5 = 14k + 2 = 2(7k + 1). Since 7k + 1 is an integer, 7n- 5 is even. q.e.d.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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