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Only two of the complex number identities below are true. Find and prove these two in detail. Remember to show all your work and label all your steps. (cos(0) + į · sin(0)) = cos(58) + į· sin(50) (cos(e) + į· sin(0))s = (cos(0))5 +į· (sin(e)) (cos(0) + į · sin(0)) = (cos(0))" + 5 cos(0) – 10 sin(0) cos(0) + 5i · sin(0) + i* · (sin(0))S ах — by + i:(bх + ay) x² – y² a + bi x + iy a + bi a b = -+i: - x + iy ах + by +i:(bx — ау) x² + y² a + bi x + iy II

Only two of the complex number identities below are true. Find and prove these two in detail. Remember to show all your work and label all your steps. (cos(0) + į · sin(0)) = cos(58) + į· sin(50) (cos(e) + į· sin(0))s = (cos(0))5 +į· (sin(e)) (cos(0) + į · sin(0)) = (cos(0))" + 5 cos(0) – 10 sin(0) cos(0) + 5i · sin(0) + i* · (sin(0))S ах — by + i:(bх + ay) x² – y² a + bi x + iy a + bi a b = -+i: - x + iy ах + by +i:(bx — ау) x² + y² a + bi x + iy II

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Please show all work and calculations in detail. Please label steps and provide explanations where possible. Thank you!

Only two of the complex number identities below are true. Find and prove these two in detail. Remember to show all your work and label all your steps. (cos(0) + į- sin(0)) = cos(50) + į· sin(50) (cos(0) + į- sin(0))5 = (cos(8))5 +į· (sin(e))5 (cos(0) + į- sin(0)) = (cos(0))5 + 5 cos(0) – 10 sin(0) cos(0) + 5i - sin(0) + i5 - (sin(0))5 ах — by +i:(bx + ay) x² – y² a + bi x + iy a + bi b = -+ L: - a x + iy a + bi ах + by +i:(bх — ау) x + iy x² + y² II
Transcribed Image Text:Only two of the complex number identities below are true. Find and prove these two in detail. Remember to show all your work and label all your steps. (cos(0) + į- sin(0)) = cos(50) + į· sin(50) (cos(0) + į- sin(0))5 = (cos(8))5 +į· (sin(e))5 (cos(0) + į- sin(0)) = (cos(0))5 + 5 cos(0) – 10 sin(0) cos(0) + 5i - sin(0) + i5 - (sin(0))5 ах — by +i:(bx + ay) x² – y² a + bi x + iy a + bi b = -+ L: - a x + iy a + bi ах + by +i:(bх — ау) x + iy x² + y² II
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