Only two of the complex number identities below are true. Find and prove these two in detail. Remember to show all your work and label all your steps. (cos(0) + į · sin(0)) = cos(58) + į· sin(50) (cos(e) + į· sin(0))s = (cos(0))5 +į· (sin(e)) (cos(0) + į · sin(0)) = (cos(0))" + 5 cos(0) – 10 sin(0) cos(0) + 5i · sin(0) + i* · (sin(0))S ах — by + i:(bх + ay) x² – y² a + bi x + iy a + bi a b = -+i: - x + iy ах + by +i:(bx — ау) x² + y² a + bi x + iy II
Only two of the complex number identities below are true. Find and prove these two in detail. Remember to show all your work and label all your steps. (cos(0) + į · sin(0)) = cos(58) + į· sin(50) (cos(e) + į· sin(0))s = (cos(0))5 +į· (sin(e)) (cos(0) + į · sin(0)) = (cos(0))" + 5 cos(0) – 10 sin(0) cos(0) + 5i · sin(0) + i* · (sin(0))S ах — by + i:(bх + ay) x² – y² a + bi x + iy a + bi a b = -+i: - x + iy ах + by +i:(bx — ау) x² + y² a + bi x + iy II
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Please show all work and calculations in detail. Please label steps and provide explanations where possible. Thank you!
![Only two of the complex number identities below are true. Find and prove these two in detail.
Remember to show all your work and label all your steps.
(cos(0) + į- sin(0)) = cos(50) + į· sin(50)
(cos(0) + į- sin(0))5 = (cos(8))5 +į· (sin(e))5
(cos(0) + į- sin(0)) = (cos(0))5 + 5 cos(0) – 10 sin(0) cos(0) + 5i - sin(0) + i5 - (sin(0))5
ах — by +i:(bx + ay)
x² – y²
a + bi
x + iy
a + bi
b
= -+ L: -
a
x + iy
a + bi
ах + by +i:(bх — ау)
x + iy
x² + y²
II](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb9a8e2f6-b575-4548-9571-8c7b98c8afa0%2F7090a033-585d-4bee-9865-069fef877619%2F8i9lkkw_processed.png&w=3840&q=75)
Transcribed Image Text:Only two of the complex number identities below are true. Find and prove these two in detail.
Remember to show all your work and label all your steps.
(cos(0) + į- sin(0)) = cos(50) + į· sin(50)
(cos(0) + į- sin(0))5 = (cos(8))5 +į· (sin(e))5
(cos(0) + į- sin(0)) = (cos(0))5 + 5 cos(0) – 10 sin(0) cos(0) + 5i - sin(0) + i5 - (sin(0))5
ах — by +i:(bx + ay)
x² – y²
a + bi
x + iy
a + bi
b
= -+ L: -
a
x + iy
a + bi
ах + by +i:(bх — ау)
x + iy
x² + y²
II
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