Only two forces act on an object (mass=4.19 kg), as the drawing. Find (a) the magnitude and (b) the direction (relative to the x axis) of the acceleration of the object. +V I I 145.0⁰ 40.0 N 60.0 N ---+x

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### Physics Problem: Determining Acceleration from Forces

#### Problem Statement:
Only two forces act on an object (mass = 4.19 kg), as depicted in the drawing. Find (a) the magnitude and (b) the direction (relative to the x-axis) of the acceleration of the object.

#### Diagram Description:
The diagram shows the object, representing as a block, on which two forces are acting. The forces are depicted as arrows:
- A 40.0 N force acting horizontally to the right (along the +x axis).
- A 60.0 N force acting at a 45.0° angle above the horizontal.

#### Questions:
(a) Calculate the magnitude of the acceleration of the object.
(b) Determine the direction of the acceleration relative to the x-axis.

#### Response Fields:
- (a) Number: ______ [Units: m/s²]
- (b) Number: ______ [Units: Degrees]

Ensure to fill in the values accurately in the provided fields.

#### Explanation:
To solve for the magnitude and direction of the acceleration, follow these detailed steps:

1. **Resolve the 60.0 N force into its components:**
   - Horizontal component: \(60.0 \, \text{N} \cos(45.0°)\)
   - Vertical component: \(60.0 \, \text{N} \sin(45.0°)\)

2. **Sum up the forces in the x and y directions:**
   - \(F_x = 40.0 \, \text{N} + 60.0 \, \text{N} \cos(45.0°)\)
   - \(F_y = 60.0 \, \text{N} \sin(45.0°)\)

3. **Calculate the net force \(F_{net}\):**
   - \(F_{net} = \sqrt{(F_x)^2 + (F_y)^2}\)

4. **Determine the acceleration using Newton's second law:**
   - \(a = \frac{F_{net}}{m}\)

5. **Find the direction of the acceleration:**
   - The angle θ with respect to the x-axis can be determined using \(\tan^{-1} \left(\frac{F_y}{F_x} \right)\)

This systematic approach ensures you obtain both the magnitude and the direction of the acceleration accurately.
Transcribed Image Text:### Physics Problem: Determining Acceleration from Forces #### Problem Statement: Only two forces act on an object (mass = 4.19 kg), as depicted in the drawing. Find (a) the magnitude and (b) the direction (relative to the x-axis) of the acceleration of the object. #### Diagram Description: The diagram shows the object, representing as a block, on which two forces are acting. The forces are depicted as arrows: - A 40.0 N force acting horizontally to the right (along the +x axis). - A 60.0 N force acting at a 45.0° angle above the horizontal. #### Questions: (a) Calculate the magnitude of the acceleration of the object. (b) Determine the direction of the acceleration relative to the x-axis. #### Response Fields: - (a) Number: ______ [Units: m/s²] - (b) Number: ______ [Units: Degrees] Ensure to fill in the values accurately in the provided fields. #### Explanation: To solve for the magnitude and direction of the acceleration, follow these detailed steps: 1. **Resolve the 60.0 N force into its components:** - Horizontal component: \(60.0 \, \text{N} \cos(45.0°)\) - Vertical component: \(60.0 \, \text{N} \sin(45.0°)\) 2. **Sum up the forces in the x and y directions:** - \(F_x = 40.0 \, \text{N} + 60.0 \, \text{N} \cos(45.0°)\) - \(F_y = 60.0 \, \text{N} \sin(45.0°)\) 3. **Calculate the net force \(F_{net}\):** - \(F_{net} = \sqrt{(F_x)^2 + (F_y)^2}\) 4. **Determine the acceleration using Newton's second law:** - \(a = \frac{F_{net}}{m}\) 5. **Find the direction of the acceleration:** - The angle θ with respect to the x-axis can be determined using \(\tan^{-1} \left(\frac{F_y}{F_x} \right)\) This systematic approach ensures you obtain both the magnitude and the direction of the acceleration accurately.
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