Only one of these calculations is correct to evaluate 1 cosx the limit lim sinx x-0 Select one: sinx – x cosx lim x sinx Cosx |= lim x-olx cosx+ sinx lim sinx x sinx x+0 x+0 1 lim sinx- x cosx x sinx coSx = lim sinx x-0 x+0 1 O im 1 = lim x+0 sinx |= 1-1=0 CoSx sinx cosx sinx- x cosx x sinx 1 lim x sinx CoSx |= lim sinx = lim x-0\x cosx+ sinx ) x→0 \ -x s = lim x+0 x+0 1 lim COSX = x - 0 = 0 sinx x+0

Q: 2. Find if possible: sin(nx) a) lim x-4 x2-16 b) lim x (sinx+(cosx)³) (x2+1)(x-3) c) lim,--o (cosx)

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A: Straightway, without any fear, put the value of 0 in the main expression to get,

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A:

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A:

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A: Solution

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A:

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A: [i]

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A: Solutions:

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.