2 cos x tan 7x 2b) find lim

Q: limg-0 2x sinx 4-4cosx

A: We can find the limit as below, using L'Hospital rule.

Q: Investigate lim sin

A:

Q: Evaluate tan 3x2 + sin² 5x lim

A: Here we have to evaluate       limx-->0[tan 3x2 + sin2 5x]/x2

Q: 1. lim tan 2x.csc 4x

A: Lim     tan2x.csc4x      ?  X-> 0

Q: 3 Lim x40 Cosx (2 Cos²x - 1) Cosx -

A:

Q: sin 5x lim, X→0

A: Given, limx→ 0sin5xx   Apply the L'Hopital's Rule: limx→ 0sin5xx=limx→ 0cos5x· 51

Q: Find the value of (a, b) so that sin 12x lim x+0 x³ cos 12x Write your answer in the form of (a, b)…

A:

Q: sin 4x What is lim X-0

A:

Q: find limx->2 X-2 tanQ. Sin O 9) tan a-sin o-tanQ. Sin

A: To find the solution of given equations

Q: Evaluate tan (7x +1) sec³(7x +

A: Given that: ∫tan5(7x+1).sec3(7x+1)dx

Q: x+2 lim sin - x+6x+8 3 2.

A:

Q: 9. Simplify sec² x - 1 sec² x

A: secx=1cosxI=sec2x-1sec2xsin2x+cos2x=1

Q: lim sin (–3 x z) = z-3

A: To find- the limit.

Q: Find the residues. of each of the fellowing functions at its. poles e •f(z)- 22+3 ans : r=714 ? z…

A:

Q: Vx+1- /2x x² - x 2х f ) lim x→1

A: As per our guidelines we are suppose to solve only first question. Kindly repost the other question…

Q: Find x + sin lim r00 x + cos x

A:

Q: tan t sec 2t 2- lim 3t

A: Using rules of limits to find the answer.

Q: (tan 4x + sec 3x) dx

A: Answer is mentioned below

Q: sin 30 25. lim 0→0 tan 20

A: Evaluate the given limit.

Q: lim, 0 6 tan² (5x) 15x²

A:

Q: Stan³ x secx dx

A:

Q: [s sec³ x tan5 x dx

A: The given integral is sec3x tan5x.

Q: sec²0-1 0 0 3 sin²0 2. Find lim

A:

Q: 1+sec2xsin2x=sec2x. Verify the identity

A: To verify the trigonometric identity given below:

Q: find lim theta ->-4, tan(theta + 4 ) / 5theta+20

A:

Q: tan 3x lim sin 8x

A: