Learning Goal:To understand polarization of light and how to useMalus's law to calculate the intensity of a beam of lightafter passing through one or more polarizing filters.Most natural light sources emit "unpolarized" light, perhaps better described as "randomly polarized" light. These light sources emitnumerous brief bursts of light whose polarization directions are unrelated, so on average the resulting beam has all polarization anglesequally represented. When unpolarized light with intensity Io passes through a polarizer, its intensity I is cut in half, regardless of theorientation of the transmission axis of the polarizer:The two transverse waves shown in the figure(Figure1) both travel in the +z direction. The waves differ inthat the top wave oscillates horizontally and thebottom wave oscillates vertically. The direction ofocillation of a wave is called the polarization of thewave. The upper wave is described as polarized in the+x direction whereas the lower wave is polarized inthe +y direction. In general, waves can be polarizedalong any direction.I = Io-Part DOne way to produce a beam of polarized light with intensity I and polarization angle 0 would be to pass unpolarized light with intensityIo through a polarizer whose transmission axis is oriented such that OTAintensity I?(Figure 3): 0. How large must Io be if the transmitted light is to haveRecall that electromagnetic waves, such as visiblelight, microwaves, and X rays, consist of oscillatingelectric and magnetic fields. The polarization of anExpress your answer as a decimal number times the symbol I. For example, if Io = (1/4)I, enter 0.25 * I.Figure3 of 3>?Io =IncidentSubmitRequest AnswernaturallightPart E Complete previous part(s)Part F Complete previous part(s)PolarizerProvide FeedbackNext >

Given information: The relation between the intensity of un-polarized Incident light (I0) and the…

Answered: One way to produce a beam of polarized…

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