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one stone falls from a cliff, a second one is thrown 3 seconds later, and they both hit the ground at the same time. Initial velocity for 1) 0m/s   2) 58.8m/s Time for 1) t  2) t+3 If I'm trying to solve for the time stone 1 took to hit the ground, shouldn't height (distance) be equal for both? The only difference is their initial velocities and time difference (i.e. t=3) I set both "change in position"-to-"constant acceleration" equations equal to each other, solved for t, and got 2.86 seconds

one stone falls from a cliff, a second one is thrown 3 seconds later, and they both hit the ground at the same time. Initial velocity for 1) 0m/s   2) 58.8m/s Time for 1) t  2) t+3 If I'm trying to solve for the time stone 1 took to hit the ground, shouldn't height (distance) be equal for both? The only difference is their initial velocities and time difference (i.e. t=3) I set both "change in position"-to-"constant acceleration" equations equal to each other, solved for t, and got 2.86 seconds

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My question tells me that one stone falls from a cliff, a second one is thrown 3 seconds later, and they both hit the ground at the same time.

Initial velocity for 1) 0m/s   2) 58.8m/s

Time for 1) t  2) t+3

If I'm trying to solve for the time stone 1 took to hit the ground, shouldn't height (distance) be equal for both? The only difference is their initial velocities and time difference (i.e. t=3)

I set both "change in position"-to-"constant acceleration" equations equal to each other, solved for t, and got 2.86 seconds

 

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