One solution of the recursion relation an+2 = n+I» n 2 0, is n+1 » a) a2k+1 = (-1)*a 2k k! k 2 0 b) None of these c) an+1 n 2 1 %3D 2" n!' d) an+1 (-1)"a 2" n!n 20 %3D e) a2k+1 = (-1)*-'as, 2k-1 k! -, k > 1 %3D

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