Question 4 Consider the group presentation 1 (a,b,cla²b²c², a¹bc¹,aba¯¹b-¹). Show that, modulo the relations, we have ba²cb¹abc²= = e. Show all steps. (Hint: Try inserting a¹bc¹ between some letters and see how this goes. Also, note that the relation aba-¹b-¹ tells us that ab = ba, it can be very useful!)

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A: Question is solved.

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A: how ba2b-1=beb-1?And a2=e?

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