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One point charge Q1=20uC is placed at (-d,0) and another Q2=-10uC at (+d,0) as shown in the figure below. Find the horizontal of the resulting field strength at a point with coordinates (x,y), where d=1.0m and x=y= 2m

One point charge Q1=20uC is placed at (-d,0) and another Q2=-10uC at (+d,0) as shown in the figure below. Find the horizontal of the resulting field strength at a point with coordinates (x,y), where d=1.0m and x=y= 2m

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One point charge Q1=20uC is placed at (-d,0) and another Q2=-10uC at (+d,0) as shown in the figure below. Find the horizontal of the resulting field strength at a point with coordinates (x,y), where d=1.0m and x=y= 2m

 

Expert Solution
Introduction:

We are given the 2 charges. 

The electric field for a charge at a given point is given as

E=kqr2

Here q,r are charge and distance of point.

We find the electric field due to both charges. We then find horizontal component of both fields and then find resultant horizontal component of net field.

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