One point charge Q1=20uC is placed at (-d,0) and another Q2=-10uC at (+d,0) as shown in the figure below. Find the horizontal of the resulting field strength at a point with coordinates (x,y), where d=1.0m and x=y= 2m

One point charge Q1=20uC is placed at (-d,0) and another Q2=-10uC at (+d,0) as shown in the figure below. Find the horizontal of the resulting field strength at a point with coordinates (x,y), where d=1.0m and x=y= 2m

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Question

One point charge Q₁=20uC is placed at (-d,0) and another Q₂=-10uC at (+d,0) as shown in the figure below. Find the horizontal of the resulting field strength at a point with coordinates (x,y), where d=1.0m and x=y= 2m

Expert Solution

Introduction:

We are given the 2 charges.

The electric field for a charge at a given point is given as

$E = \frac{k q}{r^{2}}$

Here $q, r$ are charge and distance of point.

We find the electric field due to both charges. We then find horizontal component of both fields and then find resultant horizontal component of net field.