A charge Q = 8.4 x 10-4 C is distributed uniformly along a rod of length L = 18.5 cm, extending from y = -L/2 to y = +L/2, as shown in the diagram below. A charge q = 6.85 x 10-6 C, and the same sign as Q, is placed at (D, 0), where D = 12 cm. O L/2 -L/2 D
A charge Q = 8.4 x 10-4 C is distributed uniformly along a rod of length L = 18.5 cm, extending from y = -L/2 to y = +L/2, as shown in the diagram below. A charge q = 6.85 x 10-6 C, and the same sign as Q, is placed at (D, 0), where D = 12 cm. O L/2 -L/2 D
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I cant seem to get the force calculation

Transcribed Image Text:Uniformly Charged Rod
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A charge Q 8.4 x 10-4 C is distributed uniformly along a rod of length L 18.5 cm, extending from y = −L/2 to y = +L/2, as shown in the
diagram below. A charge q = 6.85 × 10-6 C, and the same sign as Q, is placed at (D, 0), where D = 12 cm.
Conceptual
ForceCalculation
dy
fx = -3.69.10¹ N
O
L/2
-L/2
Use integration to compute the total force on q in the x direction.
r
D
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