A charge Q = 8.4 x 10-4 C is distributed uniformly along a rod of length L = 18.5 cm, extending from y = -L/2 to y = +L/2, as shown in the diagram below. A charge q = 6.85 x 10-6 C, and the same sign as Q, is placed at (D, 0), where D = 12 cm. O L/2 -L/2 D
A charge Q = 8.4 x 10-4 C is distributed uniformly along a rod of length L = 18.5 cm, extending from y = -L/2 to y = +L/2, as shown in the diagram below. A charge q = 6.85 x 10-6 C, and the same sign as Q, is placed at (D, 0), where D = 12 cm. O L/2 -L/2 D
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I cant seem to get the force calculation
![Uniformly Charged Rod
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A charge Q 8.4 x 10-4 C is distributed uniformly along a rod of length L 18.5 cm, extending from y = −L/2 to y = +L/2, as shown in the
diagram below. A charge q = 6.85 × 10-6 C, and the same sign as Q, is placed at (D, 0), where D = 12 cm.
Conceptual
ForceCalculation
dy
fx = -3.69.10¹ N
O
L/2
-L/2
Use integration to compute the total force on q in the x direction.
r
D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F980f35d1-1636-4d91-abb8-4dbf7f33a8a7%2Fa9b86a8b-c4ab-4b8d-b533-598e8fed2b65%2Fgawt6k5_processed.png&w=3840&q=75)
Transcribed Image Text:Uniformly Charged Rod
=
=
A charge Q 8.4 x 10-4 C is distributed uniformly along a rod of length L 18.5 cm, extending from y = −L/2 to y = +L/2, as shown in the
diagram below. A charge q = 6.85 × 10-6 C, and the same sign as Q, is placed at (D, 0), where D = 12 cm.
Conceptual
ForceCalculation
dy
fx = -3.69.10¹ N
O
L/2
-L/2
Use integration to compute the total force on q in the x direction.
r
D
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