One of the steps involved in the processing of corn flakes for cereals involves toasting the flakes. The accompanying table contains data for corn flakes thickness in millimeters for four different toasting times in seconds. Complete parts​ (a) through​ (d) below.   Perform a​ one-way ANOVA. Find the test statistic.   FSTAT=? ​(Type an integer or decimal rounded to two decimal places as​ needed.)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.6: Permutations
Problem 5E
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One of the steps involved in the processing of corn flakes for cereals involves toasting the flakes. The accompanying table contains data for corn flakes thickness in millimeters for four different toasting times in seconds. Complete parts​ (a) through​ (d) below.

 

Perform a​ one-way ANOVA. Find the test statistic.
 
FSTAT=?
​(Type an integer or decimal rounded to two decimal places as​ needed.)
O Corn Flake Thickness
20 sec
40 sec
60 sec
80 sec
1.1
1.5
1.7
1.8
0.8
1.6
1.4
0.7
0.8
0.7
0.7
0.4
Print
Done
Transcribed Image Text:O Corn Flake Thickness 20 sec 40 sec 60 sec 80 sec 1.1 1.5 1.7 1.8 0.8 1.6 1.4 0.7 0.8 0.7 0.7 0.4 Print Done
Critical values of the Studentized Range, Q
Upper 5% Points (a = 0.05)
Denominator,
Numerator, df
af
6 7
3
4
5
8
9.
10
17.97 26.98
32.82
37.08
40.41
43.12
45.40
47.36
13.54
49.07
2
6.09
8.33
9.80
10.88
11.74
12.44
13.03
13.99
4.50
5.91
6.83
7.50
8.04
8.48
885
9.18
9.46
3.93
5.04
5.76
6.29
6.71
7.05
7.35
7.60
7.83
3.64
4.60
5.22
5.67
6.03
6.33
658
6.80
7.00
6.
3.46
4.34
4.90
5.31
5.63
5.90
6.12
6.32
6.49
7
3.34
4.17
4.68
5.06
5.36
5.61
582
6.00
6.16
3.26
4.04
4.53
4.89
5.17
5.40
5.60
5.77
5.92
9.
3.20
3.95
4.42
4.76
5.02
5.24
5.43
5.60
5.74
10
3.15
4.33
4.65
3.88
3.82
4.91
5.12
531
5.46
5.60
11
3.11
4.26
4.57
4.82
5.03
5.20
5.35
5.49
12
3.08
3.77
4.20
4.51
4.75
4.95
5.12
5.27
5.40
5.19
513
13
3.06
3.74
4.15
4.45
4.69
4.89
5.05
5.32
14
3.03
3.70
4.11
4.41
4.64
4.83
4.99
5.25
15
3.01
3.67
4.08
4.37
4.60
4.78
4.94
5.08
5.20
16
3.00
3.65
4.05
4.33
4.56
4.74
4.90
5.03
5.15
17
2.98
3.63
4.02
4.30
4.52
4.71
4.86
4.99
5.11
18
2.97
3.61
4.00
4.28
4.50
4.67
4.82
4.96
5.07
19
2.96
3.59
3.98
4.25
4.47
4.65
4.79
4.92
5.04
20
2.95
3.58
3.96
4.23
4.45
4.62
4.77
4.90
5.01
24
2.92
3.53
3.90
4.17
4.37
4.54
4.68
4.81
4.92
30
2.89
3.49
3.85
4.10
4.30
4.46
4.60
4.72
4.82
40
2.86
3.44
3.79
4.04
4.23
4.39
4.52
4.64
4.74
60
2.83
3.40
3.74
3.98
4.16
4.31
444
4.55
4.65
3.69
3.63
120
2.80
3.36
3.92
4.10
4.24
4.36
4.47
4.56
00
2.77
3.31
3.86
4.03
4.17
4.29
4.39
4.47
Print
Done
Transcribed Image Text:Critical values of the Studentized Range, Q Upper 5% Points (a = 0.05) Denominator, Numerator, df af 6 7 3 4 5 8 9. 10 17.97 26.98 32.82 37.08 40.41 43.12 45.40 47.36 13.54 49.07 2 6.09 8.33 9.80 10.88 11.74 12.44 13.03 13.99 4.50 5.91 6.83 7.50 8.04 8.48 885 9.18 9.46 3.93 5.04 5.76 6.29 6.71 7.05 7.35 7.60 7.83 3.64 4.60 5.22 5.67 6.03 6.33 658 6.80 7.00 6. 3.46 4.34 4.90 5.31 5.63 5.90 6.12 6.32 6.49 7 3.34 4.17 4.68 5.06 5.36 5.61 582 6.00 6.16 3.26 4.04 4.53 4.89 5.17 5.40 5.60 5.77 5.92 9. 3.20 3.95 4.42 4.76 5.02 5.24 5.43 5.60 5.74 10 3.15 4.33 4.65 3.88 3.82 4.91 5.12 531 5.46 5.60 11 3.11 4.26 4.57 4.82 5.03 5.20 5.35 5.49 12 3.08 3.77 4.20 4.51 4.75 4.95 5.12 5.27 5.40 5.19 513 13 3.06 3.74 4.15 4.45 4.69 4.89 5.05 5.32 14 3.03 3.70 4.11 4.41 4.64 4.83 4.99 5.25 15 3.01 3.67 4.08 4.37 4.60 4.78 4.94 5.08 5.20 16 3.00 3.65 4.05 4.33 4.56 4.74 4.90 5.03 5.15 17 2.98 3.63 4.02 4.30 4.52 4.71 4.86 4.99 5.11 18 2.97 3.61 4.00 4.28 4.50 4.67 4.82 4.96 5.07 19 2.96 3.59 3.98 4.25 4.47 4.65 4.79 4.92 5.04 20 2.95 3.58 3.96 4.23 4.45 4.62 4.77 4.90 5.01 24 2.92 3.53 3.90 4.17 4.37 4.54 4.68 4.81 4.92 30 2.89 3.49 3.85 4.10 4.30 4.46 4.60 4.72 4.82 40 2.86 3.44 3.79 4.04 4.23 4.39 4.52 4.64 4.74 60 2.83 3.40 3.74 3.98 4.16 4.31 444 4.55 4.65 3.69 3.63 120 2.80 3.36 3.92 4.10 4.24 4.36 4.47 4.56 00 2.77 3.31 3.86 4.03 4.17 4.29 4.39 4.47 Print Done
Expert Solution
Step 1

ANOVA: The analysis of variance (ANOVA) is used to determine whether there are any statistically significant differences between the population means (μ) of more than two independents (unrelated) groups.

The null and alternative hypothesis are,

H0: There is no significant difference between the treatment means (μ).

H1: At least one treatment differs significantly.

OR

H0 : μ1 = μ2 = μ3 = μ4H1 : μ1  μ2  μ3  μ4

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