One of the reasons why the concept of an unfair coin is important in probability is that many real-life experiments can be modeled by a toss of an unfair coin. For example, if the probability of Kwan guessing the correct answer on a multiple-choice question is 0.25, then guessing the answer on a multiple-choice question can be modeled by a toss of an unfair coin for which Heads is associated with Correct and Tails with Incorrect. Thus, the probability of Kwan guessing correctly 2 answers on a multiple-choice test with 8 questions is exactly the same as the probability of getting 2 heads from tossing the coin 8 times and can be computed using the following formula P(kH/n) Chp(1-p)"-k with n=8, k-2, and p = 0.25: P(2H/8)=C-0.252-0.756-28-0.0625-0.177979 -0.3115 Find the probability of Kwan guessing correctly 3 answers on a multiple-choice test with 9 questions: (Round the answer to 4 decimal places.)
One of the reasons why the concept of an unfair coin is important in probability is that many real-life experiments can be modeled by a toss of an unfair coin. For example, if the probability of Kwan guessing the correct answer on a multiple-choice question is 0.25, then guessing the answer on a multiple-choice question can be modeled by a toss of an unfair coin for which Heads is associated with Correct and Tails with Incorrect. Thus, the probability of Kwan guessing correctly 2 answers on a multiple-choice test with 8 questions is exactly the same as the probability of getting 2 heads from tossing the coin 8 times and can be computed using the following formula P(kH/n) Chp(1-p)"-k with n=8, k-2, and p = 0.25: P(2H/8)=C-0.252-0.756-28-0.0625-0.177979 -0.3115 Find the probability of Kwan guessing correctly 3 answers on a multiple-choice test with 9 questions: (Round the answer to 4 decimal places.)
MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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![One of the reasons why the concept of an unfair coin is important in probability is that many real-life
experiments can be modeled by a toss of an unfair coin. For example, if the probability of Kwan guessing
the correct answer on a multiple-choice question is 0.25, then guessing the answer on a multiple-choice
question can be modeled by a toss of an unfair coin for which Heads is associated with Correct and Tails
with Incorrect. Thus, the probability of Kwan guessing correctly 2 answers on a multiple-choice test with 8
questions is exactly the same as the probability of getting 2 heads from tossing the coin 8 times and can be
computed using the following formula
P(kH/n) Chp(1 - p)"-k
with n = 8, k = 2, and p = 0.25:
P(2H/8)= C₂-0.252-0.75 -28-0.0625 -0.177979 = 0.3115
Find the probability of Kwan guessing correctly 3 answers on a multiple-choice test with 9 questions:
(Round the answer to 4 decimal places.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F24fbda8d-e3ef-4fa4-9d4c-ed6fd04b05ab%2F1ae27a17-2018-4269-8ccc-e432a55fdbd4%2Ftsgdf8o_processed.png&w=3840&q=75)
Transcribed Image Text:One of the reasons why the concept of an unfair coin is important in probability is that many real-life
experiments can be modeled by a toss of an unfair coin. For example, if the probability of Kwan guessing
the correct answer on a multiple-choice question is 0.25, then guessing the answer on a multiple-choice
question can be modeled by a toss of an unfair coin for which Heads is associated with Correct and Tails
with Incorrect. Thus, the probability of Kwan guessing correctly 2 answers on a multiple-choice test with 8
questions is exactly the same as the probability of getting 2 heads from tossing the coin 8 times and can be
computed using the following formula
P(kH/n) Chp(1 - p)"-k
with n = 8, k = 2, and p = 0.25:
P(2H/8)= C₂-0.252-0.75 -28-0.0625 -0.177979 = 0.3115
Find the probability of Kwan guessing correctly 3 answers on a multiple-choice test with 9 questions:
(Round the answer to 4 decimal places.)
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Given that the binomial experiment is performed in order to determine the number of possible success.
We need to find P(X=3) given n=9 and p=0.25.
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