(a) What is the probability a randomly selected chip is defective? (b) What is the probability a randomly selected chip was manufactured at Plant B given the chip is defective?

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Question 4 Please solve with simple probability rules
### Probability and Statistics: Manufacturing Defect Rates

#### Problem Statement:
Imtell manufactures computer chips at two facilities in Malaysia. The defective rate for chips manufactured at Plant A is 1.4%. The defective rate for chips manufactured at Plant B is 2.1%. 68% of all chips are manufactured at Plant A.

**Questions:**
(a) What is the probability a randomly selected chip is defective?  
(b) What is the probability a randomly selected chip was manufactured at Plant B given the chip is defective?

#### Solution:

To solve these problems, we use the concepts of probability and conditional probability. Let's define the events:
- \( A \): Chip is manufactured at Plant A.
- \( B \): Chip is manufactured at Plant B.
- \( D \): Chip is defective.

Given data:
- \( P(A) = 0.68 \) (probability that a chip is manufactured at Plant A).
- \( P(B) = 0.32 \) (probability that a chip is manufactured at Plant B, since \( P(B) = 1 - P(A) \)).
- \( P(D|A) = 0.014 \) (probability that a chip is defective given it is manufactured at Plant A).
- \( P(D|B) = 0.021 \) (probability that a chip is defective given it is manufactured at Plant B).

**To find:**

(a) The probability that a randomly selected chip is defective, \( P(D) \).

Using the law of total probability:
\[ P(D) = P(D|A)P(A) + P(D|B)P(B) \]
\[ P(D) = 0.014 \times 0.68 + 0.021 \times 0.32 \]
\[ P(D) = 0.00952 + 0.00672 \]
\[ P(D) = 0.01624 \]

So, the probability that a randomly selected chip is defective is 1.624% or 0.01624.

(b) The probability that a randomly selected chip was manufactured at Plant B, given that the chip is defective, \( P(B|D) \).

Using Bayes' theorem:
\[ P(B|D) = \frac{P(D|B)P(B)}{P(D)} \]
\[ P(B|D) = \frac{0.021 \times 0
Transcribed Image Text:### Probability and Statistics: Manufacturing Defect Rates #### Problem Statement: Imtell manufactures computer chips at two facilities in Malaysia. The defective rate for chips manufactured at Plant A is 1.4%. The defective rate for chips manufactured at Plant B is 2.1%. 68% of all chips are manufactured at Plant A. **Questions:** (a) What is the probability a randomly selected chip is defective? (b) What is the probability a randomly selected chip was manufactured at Plant B given the chip is defective? #### Solution: To solve these problems, we use the concepts of probability and conditional probability. Let's define the events: - \( A \): Chip is manufactured at Plant A. - \( B \): Chip is manufactured at Plant B. - \( D \): Chip is defective. Given data: - \( P(A) = 0.68 \) (probability that a chip is manufactured at Plant A). - \( P(B) = 0.32 \) (probability that a chip is manufactured at Plant B, since \( P(B) = 1 - P(A) \)). - \( P(D|A) = 0.014 \) (probability that a chip is defective given it is manufactured at Plant A). - \( P(D|B) = 0.021 \) (probability that a chip is defective given it is manufactured at Plant B). **To find:** (a) The probability that a randomly selected chip is defective, \( P(D) \). Using the law of total probability: \[ P(D) = P(D|A)P(A) + P(D|B)P(B) \] \[ P(D) = 0.014 \times 0.68 + 0.021 \times 0.32 \] \[ P(D) = 0.00952 + 0.00672 \] \[ P(D) = 0.01624 \] So, the probability that a randomly selected chip is defective is 1.624% or 0.01624. (b) The probability that a randomly selected chip was manufactured at Plant B, given that the chip is defective, \( P(B|D) \). Using Bayes' theorem: \[ P(B|D) = \frac{P(D|B)P(B)}{P(D)} \] \[ P(B|D) = \frac{0.021 \times 0
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