One of my homework problems asks this:   A non-conducting sphere of radius R = 9.0 cm carries a charge Q = 5.0 mC distributed uniformly throughout its volume. At what distance, measured from the center of the sphere, does the electric field reach a value equal to half its maximum value?   The correct answer is marked as 4.5 cm and 12.7 cm.   I worked out: Emax = kQ/R2   for half the max electric field, i'll use R2 for radius we need to find  Ehalf = kQ/2R2 = kQ/R22   giving me: R2 = square root of 2R2 = R*square root of 2     = 9*square root of 2 = 12.7 cm   I am unable to figure out how 4.5 cm is also the answer.

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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One of my homework problems asks this:

 

A non-conducting sphere of radius R = 9.0 cm carries a charge Q = 5.0 mC distributed uniformly throughout its volume. At what distance, measured from the center of the sphere, does the electric field reach a value equal to half its maximum value?

 

The correct answer is marked as 4.5 cm and 12.7 cm.

 

I worked out:

  • Emax = kQ/R2

 

  • for half the max electric field, i'll use R2 for radius we need to find 

Ehalf = kQ/2R= kQ/R22

 

  • giving me:

R2 = square root of 2R2 = R*square root of 2

    = 9*square root of 2 = 12.7 cm

 

I am unable to figure out how 4.5 cm is also the answer.

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