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One mole of a gas with Cp 1.39R undergoes a constant volume process from P1 = 579.01 kPa and T1 = 50°C to P2 = %3D 1569kPa. During the process the gas is internally stirred and 101.1kJ of heat is added. Determine the work input to the system in Joules.

One mole of a gas with Cp 1.39R undergoes a constant volume process from P1 = 579.01 kPa and T1 = 50°C to P2 = %3D 1569kPa. During the process the gas is internally stirred and 101.1kJ of heat is added. Determine the work input to the system in Joules.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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One mole of a gas with Cp =1.39R undergoes a constant volume process from P1 = 579.01 kPa and T1 50°C to P2 = %3D 1569kPa. During the process the gas is internally stirred and 101.1kJ of heat is added. Determine the work input to the system in Joules. (2 decimal values) Add your answer
Transcribed Image Text:One mole of a gas with Cp =1.39R undergoes a constant volume process from P1 = 579.01 kPa and T1 50°C to P2 = %3D 1569kPa. During the process the gas is internally stirred and 101.1kJ of heat is added. Determine the work input to the system in Joules. (2 decimal values) Add your answer
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