One conformation is shown below for each of four constitutional isomers of dibromocyclohexane. Use models to help in answering this question. Br Br Br Br Br Br Br Br (a) Recall that even an achiral molecule can have chiral conformations. Label each of the conformations of the molecules shown as being chiral or achiral. (b) If each of the compounds that you have labeled as having a chiral conformation were placed in a polarimeter under standard conditions, would any of them have an absolute optical rotation of 0°? Explain Your answer

One conformation is shown below for each of four constitutional isomers of dibromocyclohexane. Use models to help in answering this question. Br Br Br Br Br Br Br Br (a) Recall that even an achiral molecule can have chiral conformations. Label each of the conformations of the molecules shown as being chiral or achiral. (b) If each of the compounds that you have labeled as having a chiral conformation were placed in a polarimeter under standard conditions, would any of them have an absolute optical rotation of 0°? Explain Your answer

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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ANSWER THE FOLLOWING PROBLEM AND EXPLAIN YOUR ANSWER FOR BETTER UNDERSTANDING
(c) Answer the following questions: It is possible for a compound to be chiral even though it lacks a carbon atom with four different groups. Using two nitro groups, one isopropyl group and one carboxy group as substituents, draw the structure of an optically active biphenyl that is void of a chiral carbon. i. ii. Deduce, giving reasons, whether or not the following molecules are optically active. H3C CH3 ČH(CH3)2 Quaternary ammonium salt NH2 Compound A НОСІНС OCH3 OCH3 Br Compound B
Use flat representation of rings, not chair in the drawing. Determine the most and least stable. Consider the most stable chair for each of these isomers, and then draw the most stable and least stable isomer based on a comparison of the best chair for each one.
8) For each of the pairs of molecules drawn below, place letters in the corner boxes corresponding to all accurate descriptions of the relationship between the two molecules. a) b) c) HO F A enantiomers F all letters that apply H H OH Вад CI all letters that apply all letters that apply B diastereomers C different conformations of the same molecule D identical conformations of the same molecule E constitutional isomers F stereoisomers G different molecules H both are chiral I neither is chiral
Explain your answer. I have the solutions to the questions. The instructor has given us the answer key. I still don't get the professor's answers. It's only the second part of the problem.
or (2) Give an official name to the following chiral including the notation of asymmetric centers. Br u (3) Draw the most stable chair conformation of the 2 CI
Several compounds are shown below. For each, make two models: one model of the compound as shown, and the other where each tetrahedral stereocenter is inverted. Compare the two models side-by-side to see if the model with the inverted stereocenter(s) is the enantiomer, or if it is identical to the original. Remember, you can rotate around o-bonds to place the molecule in the conformation with the highest symmetry. Is each compound meso or not? OH OH OH OH DOKOOK OH OH Compound 1 Compound 2 Compound 1's mirror image is identical to Compound 1 Compound 1's mirror image is the enantiomer of Compound 1 Compound 1 is meso Compound 2's mirror image is identical to Compound 2 Compound 2's mirror image is the enantiomer of Compound 2 Compound 2 is meso Compound 3's mirror image is identical to Compound 3 Compound 3's mirror image is the enantiomer of Compound 3 Compound 3 is meso Compound 4's mirror image is identical to Compound 4 Compound 4's mirror image is the enantiomer of Compound 4…