α = 0.51552CONNECTED3. Newborn babies are more likely to be boys than girls. A random sample found 13,173 boys wereborn among 25,468 newborn children. The sample proportion of boys was 0.5172. Is this sampleevidence that the birth of boys is more common than the birth of girls in the entire population?Ho: p = 0.5Ha: p > 0.5It is a non-directional or two-tailed test.CORRECTED:ERROR:4. Traditionally, about 70% of students in a Statistics course at ECC are successful. If only 15students in a class of 28 randomly selected students are successful, is there enough evidence at 5%level of significance to say that students of a particular instructor are successful at a rate of less than70%?Ha: p < 0.70Ho: p = 0.70P-value = 0.0289Since P-value <, we fail to reject the null hypothesis (Ho).CORRECTED:ERROR:

The provided information is p^=0.5172p=0.5n=25468The null and alternative hypothesis is…

Answered: on. VONNEUTED. 3. Newborn babies are…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The mean number of sick days an employee takes per year is believed to be about 10. Members of a personnel department do not believe this figure. They randomly survey 8 employees. The number of sick days they took for the past year are as follows: 10; 5; 13; 3; 11; 8; 6; 9. Let X = the number of sick days they took for the past year. Should the personnel team believe that the mean number is about 10? Conduct a hypothesis test at the 5% level.Note: If you are using a Student's t-distribution for the problem, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.) What is the test statistic? (If using the z distribution round your answers to two decimal places, and if using the t distribution round your answers to three decimal places.) t = Construct a 95% confidence interval for the true mean. Sketch the graph of the situation. Label the point estimate and the lower and upper bounds of the confidence…
The average house has 15 paintings on its walls. Is the mean larger for houses owned by teachers? The data show the results of a survey of 16 teachers who were asked how many paintings they have in their houses. Assume that the distribution of the population is normal. 18, 15, 17, 14, 16, 17, 18, 15, 15, 14, 14, 14, 15, 15, 16, 18 What can be concluded at the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: Select an answer v H1: Select an answer v c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the population mean is not significantly more than 15 at a = 0.05, so there is sufficient evidence to conclude that the population mean number of paintings that are in…
Each person in random samples of 227 male and 293 female working adults living in a certain town in Canada was asked how long, in minutes, his or her typical daily commute was. Is there enough evidence to show that there is a difference in mean commute times for male and female working residents of this town? (Use males females) Male Female Sample size X S Sample size x S 227 30.2 24.0 293 27.9 24.3 Find the test statistic. (Round your answer to two decimal places.) Find the df. (Round your answer down to the nearest whole number.) df= Use technology to find the P-value. (Round your answer to four decimal places.) P-value= Is there enough evidence to show that there is a difference in mean commute times for male and female working residents of this town? Use a significance level of 0.05. Yes No
Q.19 Urgent question! I will thumbs up! In the final answer that you circle, please also include the brief approach / formula you used under "Answer". Thanks!
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4 4G I. moodle.unizwa.edu.om a | Quiz3 Time left 0:00:21 Question 3 Answer saved Marked out of 2.00 P Flag question Which one of the following choices describes a problem for which an analysis of variance would be appropriate? O A. Comparing the proportion of successes for three different treatments of anxiety. Each treatment is tried on 100 patients O B. Analyzing the relationship between high school GPA and college GPA O . Analyzing the relationship between gender and opinion about capital punishment (favor or oppose). O D. Comparing the mean birth weights of newborn babies for three different hospitals. O E. None of these Clear my choice Previous page Next page 1 2w-ANOVA(3) Jump to... Quiz navigation 7 +
a.What decision can you make? b. What does that decision mean? c. What type of error could you be making, and what would it mean?
please complete the blank problem and or ones with a red x next to it not ones with a green check next to please
Question 2 > The average number of cavities that thirty-year-old Americans have had in their lifetimes is 7. Do twenty- year-olds have a different number of cavities? The data show the results of a survey of 14 twenty-year-olds who were asked how many cavities they have had. Assume that the distribution of the population is normal. 7, 8, 7, 7, 9, 7, 10, 9, 8, 10, 6, 9, 6, 8 What can be concluded at the a = 0.05 level of significance? %3D a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: |? Select an answer H1: Select an answer v c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that . The data suggest the populaton mean is significantly different from 7 at a = 0.05, so there is sufficient evidence to conclude that the…

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