on the parabola when the line intersects, but does not cross, and graph the 51. x + 4x - 6y = 53. y2 + x + y = 0 16. Focus: G, 0) 18. Focus: (0, - 1) uation with O, and (d).] 15. Focus: (0,) 17. Focus: (-2, 0) 19. Directrix: y = 2 OO Finding a Parab equation at the gi 20. Directrix: y = -4 22. Directrix: x = 3 21. Directrix: x = - 1 %3D 23. Vertical axis; passes through the point (4, 6) 24. Vertical axis; passes through the point (-3, - 3) 25. Horizontal axis; passes through the point (-2, 5) 26. Horizontal axis; passes through the point (3, - 2) 55. x2 = 8y х 8. 4 DXO Finding the Standard Equation of a Parabola In Exercises 27-36, find the standard form of the equation of the parabola 4 -4 -4 with the given characteristics. 57. x = 2y, (4, 8 %3D 27. 28. Vertex 59. y = -2r², (- (2, 6) 61. Flashlight focus of the pa Focus (-3, 0) •Focus (2, 4) vertex of ther 4 8 12 Vertex a cross section (-4, 0) -8 on the positiv ation of a 6, find the the parabola nd vertex at -1 +1 2 3 4 5 6 29. Vertex: (6, 3); focus: (4, 3) 30. Vertex: (1, - 8); focus: (3, –8) 31. Vertex: (0, 2); directrix: y = 4 32. Vertex: (1, 2); directrix: y = -1 33. Focus: (2, 2); directrix: x = -2 34. Focus: (0, 0); directrix: y = 8 35. Vertex: (3, - 3); vertical axis; passes through the point (0, 0) 36. Vertex: (-1, 6); horizontal axis; passes through the point (-9, 2) Figure for 4. 62. Satellite dish is at th equation fo 76 4321
on the parabola when the line intersects, but does not cross, and graph the 51. x + 4x - 6y = 53. y2 + x + y = 0 16. Focus: G, 0) 18. Focus: (0, - 1) uation with O, and (d).] 15. Focus: (0,) 17. Focus: (-2, 0) 19. Directrix: y = 2 OO Finding a Parab equation at the gi 20. Directrix: y = -4 22. Directrix: x = 3 21. Directrix: x = - 1 %3D 23. Vertical axis; passes through the point (4, 6) 24. Vertical axis; passes through the point (-3, - 3) 25. Horizontal axis; passes through the point (-2, 5) 26. Horizontal axis; passes through the point (3, - 2) 55. x2 = 8y х 8. 4 DXO Finding the Standard Equation of a Parabola In Exercises 27-36, find the standard form of the equation of the parabola 4 -4 -4 with the given characteristics. 57. x = 2y, (4, 8 %3D 27. 28. Vertex 59. y = -2r², (- (2, 6) 61. Flashlight focus of the pa Focus (-3, 0) •Focus (2, 4) vertex of ther 4 8 12 Vertex a cross section (-4, 0) -8 on the positiv ation of a 6, find the the parabola nd vertex at -1 +1 2 3 4 5 6 29. Vertex: (6, 3); focus: (4, 3) 30. Vertex: (1, - 8); focus: (3, –8) 31. Vertex: (0, 2); directrix: y = 4 32. Vertex: (1, 2); directrix: y = -1 33. Focus: (2, 2); directrix: x = -2 34. Focus: (0, 0); directrix: y = 8 35. Vertex: (3, - 3); vertical axis; passes through the point (0, 0) 36. Vertex: (-1, 6); horizontal axis; passes through the point (-9, 2) Figure for 4. 62. Satellite dish is at th equation fo 76 4321
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
How do you answer 33?
(This is not graded but, rather, an exercise to achieve acquisition).
![on the parabola when the line intersects, but does not cross,
and
graph the
51. x + 4x - 6y =
53. y2 + x + y = 0
16. Focus: G, 0)
18. Focus: (0, - 1)
uation with
O, and (d).]
15. Focus: (0,)
17. Focus: (-2, 0)
19. Directrix: y = 2
OO Finding
a Parab
equation
at the gi
20. Directrix: y = -4
22. Directrix: x = 3
21. Directrix: x = - 1
%3D
23. Vertical axis; passes through the point (4, 6)
24. Vertical axis; passes through the point (-3, - 3)
25. Horizontal axis; passes through the point (-2, 5)
26. Horizontal axis; passes through the point (3, - 2)
55.
x2 = 8y
х
8.
4
DXO Finding the Standard Equation of a
Parabola In Exercises 27-36, find the
standard form of the equation of the parabola
4
-4
-4
with the given characteristics.
57. x = 2y, (4, 8
%3D
27.
28.
Vertex
59. y = -2r², (-
(2, 6)
61. Flashlight
focus of the pa
Focus
(-3, 0)
•Focus
(2, 4)
vertex of ther
4 8 12
Vertex
a cross section
(-4, 0)
-8
on the positiv
ation of a
6, find the
the parabola
nd vertex at
-1 +1 2 3 4 5 6
29. Vertex: (6, 3); focus: (4, 3)
30. Vertex: (1, - 8); focus: (3, –8)
31. Vertex: (0, 2); directrix: y = 4
32. Vertex: (1, 2); directrix: y = -1
33. Focus: (2, 2); directrix: x = -2
34. Focus: (0, 0); directrix: y = 8
35. Vertex: (3, - 3); vertical axis; passes through the point
(0, 0)
36. Vertex: (-1, 6); horizontal axis; passes through the
point (-9, 2)
Figure for
4.
62. Satellite
dish is at th
equation fo
76
4321](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff41e2e4b-5a8b-4192-b824-708f7e11e022%2Fd069037d-07ec-4a5c-9064-80357153d17c%2F6wwbx2k.jpeg&w=3840&q=75)
Transcribed Image Text:on the parabola when the line intersects, but does not cross,
and
graph the
51. x + 4x - 6y =
53. y2 + x + y = 0
16. Focus: G, 0)
18. Focus: (0, - 1)
uation with
O, and (d).]
15. Focus: (0,)
17. Focus: (-2, 0)
19. Directrix: y = 2
OO Finding
a Parab
equation
at the gi
20. Directrix: y = -4
22. Directrix: x = 3
21. Directrix: x = - 1
%3D
23. Vertical axis; passes through the point (4, 6)
24. Vertical axis; passes through the point (-3, - 3)
25. Horizontal axis; passes through the point (-2, 5)
26. Horizontal axis; passes through the point (3, - 2)
55.
x2 = 8y
х
8.
4
DXO Finding the Standard Equation of a
Parabola In Exercises 27-36, find the
standard form of the equation of the parabola
4
-4
-4
with the given characteristics.
57. x = 2y, (4, 8
%3D
27.
28.
Vertex
59. y = -2r², (-
(2, 6)
61. Flashlight
focus of the pa
Focus
(-3, 0)
•Focus
(2, 4)
vertex of ther
4 8 12
Vertex
a cross section
(-4, 0)
-8
on the positiv
ation of a
6, find the
the parabola
nd vertex at
-1 +1 2 3 4 5 6
29. Vertex: (6, 3); focus: (4, 3)
30. Vertex: (1, - 8); focus: (3, –8)
31. Vertex: (0, 2); directrix: y = 4
32. Vertex: (1, 2); directrix: y = -1
33. Focus: (2, 2); directrix: x = -2
34. Focus: (0, 0); directrix: y = 8
35. Vertex: (3, - 3); vertical axis; passes through the point
(0, 0)
36. Vertex: (-1, 6); horizontal axis; passes through the
point (-9, 2)
Figure for
4.
62. Satellite
dish is at th
equation fo
76
4321
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.Recommended textbooks for you

Algebra and Trigonometry (6th Edition)
Algebra
ISBN:
9780134463216
Author:
Robert F. Blitzer
Publisher:
PEARSON

Contemporary Abstract Algebra
Algebra
ISBN:
9781305657960
Author:
Joseph Gallian
Publisher:
Cengage Learning

Linear Algebra: A Modern Introduction
Algebra
ISBN:
9781285463247
Author:
David Poole
Publisher:
Cengage Learning

Algebra and Trigonometry (6th Edition)
Algebra
ISBN:
9780134463216
Author:
Robert F. Blitzer
Publisher:
PEARSON

Contemporary Abstract Algebra
Algebra
ISBN:
9781305657960
Author:
Joseph Gallian
Publisher:
Cengage Learning

Linear Algebra: A Modern Introduction
Algebra
ISBN:
9781285463247
Author:
David Poole
Publisher:
Cengage Learning

Algebra And Trigonometry (11th Edition)
Algebra
ISBN:
9780135163078
Author:
Michael Sullivan
Publisher:
PEARSON

Introduction to Linear Algebra, Fifth Edition
Algebra
ISBN:
9780980232776
Author:
Gilbert Strang
Publisher:
Wellesley-Cambridge Press

College Algebra (Collegiate Math)
Algebra
ISBN:
9780077836344
Author:
Julie Miller, Donna Gerken
Publisher:
McGraw-Hill Education