Television Set Ownership According to Nielsen Media Research, of all the U.S. households that owned at least one television set, 83% had two or more sets. A local cable company canvassing the town to promote a new cable service found that of the 295 households visited, 241 had two or more television sets. At a = 0.05, is there sufficient evidence to conclude that the proportion is less than the one in the report? Do not round intermediate steps. Part: 0 / 5 Part 1 of 5 (a) State the hypotheses and identify the claim. Ho: |(Choose one) H : (Choose one) This hypothesis test is a (Choose one) v test.

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The first pic is the question, since I’ve been receiving some incorrect answers from the tutors, I included an example problem in the second pic
Television Set Ownership According to Nielsen Media Research, of all the U.S. households that owned at least one
television set, 83% had two or more sets. A local cable company canvassing the town to promote a new cable service
found that of the 295 households visited, 241 had two or more television sets. At a= 0.05, is there sufficient evidence to
conclude that the proportion is less than the one in the report? Do not round intermediate steps.
Part: 0 / 5
Part 1 of 5
(a) State the hypotheses and identify the claim.
Ho :
(Choose one) ▼
H :
(Choose one) ▼
This hypothesis test is a (Choose one) ▼ test.
Transcribed Image Text:Television Set Ownership According to Nielsen Media Research, of all the U.S. households that owned at least one television set, 83% had two or more sets. A local cable company canvassing the town to promote a new cable service found that of the 295 households visited, 241 had two or more television sets. At a= 0.05, is there sufficient evidence to conclude that the proportion is less than the one in the report? Do not round intermediate steps. Part: 0 / 5 Part 1 of 5 (a) State the hypotheses and identify the claim. Ho : (Choose one) ▼ H : (Choose one) ▼ This hypothesis test is a (Choose one) ▼ test.
Sample Question
Television Set Ownership According to Nielsen Media Research, of all the U.S. households that owned at least one
television set, 83% had two or more sets. A local cable company canvassing the town to promote a new cable
service found that of the 295 households visited, 234 had two or more television sets. At a = 0.01, is there sufficient
evidence to conclude that the proportion is less than the one in the report? Do not round intermediate steps.
(a) State the hypotheses and identify the claim.
(b) Find the critical value.
(c) Compute the test value.
(d) Make the decision.
(e) Summarize the results.
Explanation
(a) State the hypotheses and identify the claim.
The null hypothesis H, is the statement that there is no difference between a parameter and a specific value. This is
equivalent to p= 0.83.
The alternative hypothesis H is the statement that there is a difference between a parameter and a specific value.
In this case, the proportion is less than the one in the report. This is equivalent to p< 0.83.
The problem asks, "Is there sufficient evidence to conclude that the proportion is less than the one in the report?"
Hence, the claim is the alternative hypothesis H.
(b) Find the critical value.
From the figure, for a left-tailed test with a=0.01, the critical value is z=-2.33.
Summary of
Hypothesis
Testing and
Critical Values
a-0.10, C.V. -1.28
a = 0.05, C.V.=-1.65
H, : u<k
a=0.01, C.V.=-2.33
(a) Left-tailed
a = 0.10, C.V.= +1.28
a=0.05, C.V.-+1.65
H :u>k
a= 0.01, C.V.= +2.33
(b) Right-tailed
a = 0.10, C.V.=±1.65
a-0.05, C.V.-f1.96
H, :u#k
a=0.01, C.V.=+2.58
(c) Two-tailed
(c) Compute the test value.
First, it is necessary to find p, p, and q.
234
295
= 0.793
p - 83%
= 0.83
q =1-p
= 1-0.83
= 0.17
Using the formula for the z test for proportions, compute the test value:
Vpg'n
Transcribed Image Text:Sample Question Television Set Ownership According to Nielsen Media Research, of all the U.S. households that owned at least one television set, 83% had two or more sets. A local cable company canvassing the town to promote a new cable service found that of the 295 households visited, 234 had two or more television sets. At a = 0.01, is there sufficient evidence to conclude that the proportion is less than the one in the report? Do not round intermediate steps. (a) State the hypotheses and identify the claim. (b) Find the critical value. (c) Compute the test value. (d) Make the decision. (e) Summarize the results. Explanation (a) State the hypotheses and identify the claim. The null hypothesis H, is the statement that there is no difference between a parameter and a specific value. This is equivalent to p= 0.83. The alternative hypothesis H is the statement that there is a difference between a parameter and a specific value. In this case, the proportion is less than the one in the report. This is equivalent to p< 0.83. The problem asks, "Is there sufficient evidence to conclude that the proportion is less than the one in the report?" Hence, the claim is the alternative hypothesis H. (b) Find the critical value. From the figure, for a left-tailed test with a=0.01, the critical value is z=-2.33. Summary of Hypothesis Testing and Critical Values a-0.10, C.V. -1.28 a = 0.05, C.V.=-1.65 H, : u<k a=0.01, C.V.=-2.33 (a) Left-tailed a = 0.10, C.V.= +1.28 a=0.05, C.V.-+1.65 H :u>k a= 0.01, C.V.= +2.33 (b) Right-tailed a = 0.10, C.V.=±1.65 a-0.05, C.V.-f1.96 H, :u#k a=0.01, C.V.=+2.58 (c) Two-tailed (c) Compute the test value. First, it is necessary to find p, p, and q. 234 295 = 0.793 p - 83% = 0.83 q =1-p = 1-0.83 = 0.17 Using the formula for the z test for proportions, compute the test value: Vpg'n
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