On the head side of a hydraulic cylinder, the rod is 1/2 inch in diameter and the piston is 2 inches in diameter. Calculate the force applied while retracting the rod and the speed at which it moves if the operating pressure is 150 psi and the flow rate is 6.5 gpm. Answer is incomplete without units.
On the head side of a hydraulic cylinder, the rod is 1/2 inch in diameter and the piston is 2 inches in diameter. Calculate the force applied while retracting the rod and the speed at which it moves if the operating pressure is 150 psi and the flow rate is 6.5 gpm. Answer is incomplete without units.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
![**Title: Hydraulic Cylinder Force and Speed Calculation**
**Problem Statement:**
On the head side of a hydraulic cylinder, the rod is 1/2 inch in diameter and the piston is 2 inches in diameter. Calculate the force applied while retracting the rod and the speed at which it moves if the operating pressure is 150 psi and the flow rate is 6.5 gpm. Answer is incomplete without units.
**Explanation:**
This exercise involves calculating both the force exerted by a hydraulic cylinder during retraction and the speed of the rod movement. Key parameters provided include:
- **Rod Diameter:** 1/2 inch
- **Piston Diameter:** 2 inches
- **Operating Pressure:** 150 psi (pounds per square inch)
- **Flow Rate:** 6.5 gpm (gallons per minute)
**Key Concepts:**
1. **Force Calculation:**
- The area on which the pressure acts is critical for computing force.
- The force can be calculated using the formula:
\[
\text{Force} = \text{Pressure} \times \text{Area}
\]
2. **Speed Calculation:**
- Speed can be determined from the flow rate and the area.
- The formula for speed \( V \) is:
\[
V = \frac{\text{Flow Rate}}{\text{Area}}
\]
**Units:**
Ensure that all final answers are given with appropriate units to maintain clarity and precision in communication.
**Note:** Calculation steps using these formulas can further aid in understanding the relationship between pressure, area, force, flow rate, and speed in hydraulic systems.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa0e8d9cc-7c29-4fd3-80ef-e49f7fd479b0%2Fd04d7fdf-4f74-4f38-bc81-7de79194a722%2Fbpbjbus_processed.png&w=3840&q=75)
Transcribed Image Text:**Title: Hydraulic Cylinder Force and Speed Calculation**
**Problem Statement:**
On the head side of a hydraulic cylinder, the rod is 1/2 inch in diameter and the piston is 2 inches in diameter. Calculate the force applied while retracting the rod and the speed at which it moves if the operating pressure is 150 psi and the flow rate is 6.5 gpm. Answer is incomplete without units.
**Explanation:**
This exercise involves calculating both the force exerted by a hydraulic cylinder during retraction and the speed of the rod movement. Key parameters provided include:
- **Rod Diameter:** 1/2 inch
- **Piston Diameter:** 2 inches
- **Operating Pressure:** 150 psi (pounds per square inch)
- **Flow Rate:** 6.5 gpm (gallons per minute)
**Key Concepts:**
1. **Force Calculation:**
- The area on which the pressure acts is critical for computing force.
- The force can be calculated using the formula:
\[
\text{Force} = \text{Pressure} \times \text{Area}
\]
2. **Speed Calculation:**
- Speed can be determined from the flow rate and the area.
- The formula for speed \( V \) is:
\[
V = \frac{\text{Flow Rate}}{\text{Area}}
\]
**Units:**
Ensure that all final answers are given with appropriate units to maintain clarity and precision in communication.
**Note:** Calculation steps using these formulas can further aid in understanding the relationship between pressure, area, force, flow rate, and speed in hydraulic systems.
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