On hot, sunny, summer days, Jane rents inner tubes by the river that runs through her town. Based on her past experience, she has assigned the following probability distribution to the number of tubes she will rent on a randomly selected day. 25 50 75 100 Total P(x) .10 .34 .36 .20 1.00 (a) Find the probability expressions: (Round your answers to 2 decimal places.) a. P(X = 25) b. P(X S 50) P(X > 25) d. P(X < 75) C. (b) Which of the probability expressions in parts (a)-(d) is a value of the CDF? O Part (a) O Part (b) O Part (c) O Part (d)

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vork: Chapter 6 (Sections 6.1 through 6.4) i
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On hot, sunny, summer days, Jane rents inner tubes by the river that runs through her town. Based on her past experience, she has
assigned the following probability distribution to the number of tubes she will rent on a randomly selected day.
50
75
.36
25
100
Total
P(x).10
34
.20
1.00
(a) Find the probability expressions: (Round your answers to 2 decimal places.)
要
a. P(X = 25)
b. P(X S 50)
P(X > 25)
d. P(X < 75)
%3D
C.
(b) Which of the probability expressions in parts (a)-(d) is a value of the CDF?
O Part (a)
O Part (b)
O Part (c)
Part (d)
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Transcribed Image Text:mheducation.com/ext/map/index.html?_con3Dcon&external_browser=0&launchurl=https%253A%252F%252Fnewconnect.mheducation.com%252F#/activity vork: Chapter 6 (Sections 6.1 through 6.4) i Saved Help Save On hot, sunny, summer days, Jane rents inner tubes by the river that runs through her town. Based on her past experience, she has assigned the following probability distribution to the number of tubes she will rent on a randomly selected day. 50 75 .36 25 100 Total P(x).10 34 .20 1.00 (a) Find the probability expressions: (Round your answers to 2 decimal places.) 要 a. P(X = 25) b. P(X S 50) P(X > 25) d. P(X < 75) %3D C. (b) Which of the probability expressions in parts (a)-(d) is a value of the CDF? O Part (a) O Part (b) O Part (c) Part (d) < Prev 2 of 9 Next >
Expert Solution
Step 1

(a)

a. P( X=25)  =0.10 ( from table given) 

b. 

P(X50)= P(X=25) +P(X=50)                 =0.10+0.34                 =0.44

c. 

P(X>25) = 1-P(X25)                  =1-0.1                  =0.90

d.

P(X<75) = 1- P(X75)                   =1-(P(X=75)+P(X=100))                   =1-(0.36+0.2)                   =0.44

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