**Understanding the Distribution of Indoor Cats' Lifespan**On average, indoor cats live to 12 years old with a standard deviation of 2.4 years. Suppose that the distribution is normal. Let $ X $ represent the age at death of a randomly selected indoor cat. Round answers to four decimal places where possible.### Tasks:**a. Determine the Distribution of $ X $:**What is the distribution of $ X $? Express $ X $ as:\[ X \sim N(\text{mean}, \text{standard deviation}) \]- Mean: $\_\_\_\_\_\_\_\_\_\_$- Standard Deviation: $\_\_\_\_\_\_\_\_\_\_$**b. Probability Calculation:**Find the probability that an indoor cat dies when it is between 9.8 and 10.8 years old.\[ \_\_\_\_\_\_\_\_\_ \]**c. Percentile Range:**The middle 50% of indoor cats' age of death lies between which two numbers?- Low: $\_\_\_\_\_\_\_\_\_ $ years- High: $\_\_\_\_\_\_\_\_\_ $ years

It is given that the, On average, indoor cats live to 12 years old with a standard deviation of 2.4…

Answered: On average, indoor cats live to 12…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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pr The lengths of pregnancies are normally distributed with a mean of 269 days and a standard deviation of 15 days. a. Find the probability of a pregnancy lasting 308 days or longer. b. If the length of pregnancy is in the lowest 4%, then the baby is premature. Find the length that separates premature babies from those who are not premature. /2 pr Click to view page 1 of the table. Click to view page 2 of the table. /2 a. The probability that a pregnancy will last 308 days or longer is (Round to four decimal places as needed.) pr b. Babies who are born on or before 12 days are considered premature. (Round to the nearest integer as needed.) /2 12 uc /2 12 or /2 or (2 Enter your answer in each of the answer boxes.
The average number of words in a romance novel is 64,159 and the standard deviation is 17,401. Assume the distribution is normal. Let X be the number of words in a randomly selected romance novel. Round all answers to 4 decimal places where possible.a. What is the distribution of X? X ~ N(__________ , ___________) b. Find the proportion of all novels that are between 50,238 and 58,939 words. _______________c. The 85th percentile for novels is_____________________ words. (Round to the nearest word)d. The middle 60% of romance novels have from ______________ words to ________________words. (Round to the nearest word)
Provide an appropriate response. Use the Standard Normal Table to find the probability. IQ test scores are normally distributed with a mean of 100 and a standard deviation of 15. An individual's IQ score is found to be 90. Find the z-score corresponding to this value. OA. -1.33 OB. 1.33 OC. 0.67 O D. -0.67 C
A normal distribution has a mean of 85 and a standard deviation of 6. Find the z-score for a data value of 92. places Round to two decimal
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The average grade for an exam is 74, the standard deviation is 7 and the grades are curved to follow a normal distribution. Find the probability that a student will get a grade from 81 to 88 Select one: O a. 0.451 b. 0.612 O c. 0.1359 O d. 0.561
The time between arrivals of vehicles at a particular intersection follows an exponential probability distribution with a mean of 12 seconds. A. IN EXCEL sketch this exponential distribution, and Standard deviation. B. IN EXCEL What is the probability that the arrival time between vehicles is 12 seconds or less. C. IN EXCEL What is the probability that the arrival time between vehicles is 6 seconds or less.
The average price of a new one-family home is $180,000 with a standard deviation of $14,000. Find the probability that a randomly selected house will have a price between $150,000 and $200,000. Assume the variable is normally distributed. Write your answer correct to four decimal places. Your Answer: Answer
e average American man consumes 9.6 grams of sodium each day. ppose that the sodium consumption of American men is normally stributed with a standard deviation of 0.8 grams. Suppose an American nan is randomly chosen. Let X = the amount of sodium consumed. Round Al numeric answers to 4 decimal places where possible. %3D a. What is the distribution of X? X - N( b. Find the probability that this American man consumes between 9.5 and 10.6 grams of sodium per day. c. The middle 20% of American men consume between what two weights of sodium? Low: High:
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Assume that adults have IQ scores that are normally distributed with a mean of u = 105 and a standard deviation o = 15. Find the probability that a randomly selected adult has an IQ between 89 and 121. Click to view page 1 of the table. Click to view page 2 of the table. Standard Normal Table (Page 2) The probability that a randomly selected adult has an IQ between 89 and 121 is (Type an integer or decimal rounded to four decimal places as needed.) POSITIVE z Scores Standard Normal (z) Distribution: Cumulative Area from the LEFT .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 0.0 .5000 .5040 .5080 .5120 .5160 .5199 .5239 5279 .5319 .5359 0.1 .5398 .5438 5478 .5517 .5557 .5596 ,5636 ,5675 .5714 .5753 0.2 .5793 .5832 5871 5910 .5948 .5987 .6026 .6064 .6103 .6141 0.3 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 .6480 .6517 0.4 .6554 .6591 .6628 .6664 .6700 .6736 .6772 .6808 .6844 .6879 0.5 .6915 6950 .6985 7019 .7054 .7088 7123 7157 .7190 .7224 0.6 .7257 .7291 7324 7357 7389 7422 7454 7486…

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