On a shaper, a workpiece with a tool machining stroke L = 4000 mm and a width B = 1000 mm will be processed in the pass. The cutting time of the tool is tc = 10 s, the rotation time is tr = 5 s. In this process; a) Machine power, b) Main machining time, c) Find the double stroke number of the tool. (f = 1,5 mm/çs, ap = 10 mm, kc = 2200 N/mm2 , ņM = O,6) %3D %3D %3D

On a shaper, a workpiece with a tool machining stroke L = 4000 mm and a width B = 1000 mm will be processed in the pass. The cutting time of the tool is tc = 10 s, the rotation time is tr = 5 s. In this process; a) Machine power, b) Main machining time, c) Find the double stroke number of the tool. (f = 1,5 mm/çs, ap = 10 mm, kc = 2200 N/mm2 , ņM = O,6) %3D %3D %3D

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

λ= te average Vc = MDN 1000 T = S sin Where λ is Chip Reduction Coefficient Vc is cutting speed te is thickness of cut chip T is thickness of non-cut chip S is feed rate Ⓒ is cutting angle = 45⁰ D is diameter of workpiece = 40mm Results m/min Depth of cut (a) mm 22222 Cutting speed (Vc) m/min 500 500 500 500 500 Feed rate (S) mm/rev Required: 1.Complete the solution to the table with the given rules 2-Draw chart between feed rate (S) and chip reduction coefficient 2 tc: tc₂ tcs 0.11 0.39 0.58 0.43 0.14 0.42 0.62 0.5 0.20 0.34 0.42 0.32 0.24 0.9 0.96 0.95 0.28 0.92 0.85 0.85 te average (mm) T (mm) with discuss it. Chip Reduction Coefficient (2)
A job has to be machined in shaping and the process parameters are given below: Length of the job=120 mm Speed of the motor=640 rpm Cutting speed=248 m/min Tool allowance before cutting =31.5 mm Tool allowance after cutting=10 mm Determine the cutting to return stroke ratio for the above operation and draw the arrangement of machining with tool head and allowances.
The following data were obtained from a time study performed on a horizontal milling machine: Average manual effort time per cycle: 4.62 minutes. Average cutting time (electric feed): 3.74 minutes. Average performance rating: 115%.Machine clearance (power supply): 10% Fatigue clearance: 15%. What is the standard time for the operation?
life for minimum cost given that cost of 1 cutting speed is the only variable based on the cutting In a single pass turning operation the cutting time cost and the cutting edge cost. The tool edge is 5, operator wages including the machine tool cost is ? 75/hour and tool life equation is VTO.1 is 100 (a) 10 (b) 17 (d) 36 (c) 29
The following data were obtained from a time study performed on a horizontal milling machine: Average manual effort time per cycle: 4.62 minutes. Average cutting time (electric feed): 3.74 minutes. Average performance rating: 115%. Backlash due to machine (power supply): 10%. Slack due to fatigue: 15%. What is the standard time for the operation?
7-Which of the following lathe operations requires that the cutting edge of a tool bit be placed exactly on the work center line... а) Boring. b) Drilling. c) Facing. d) Turning. 8-In lathe, the carriage and tail stock are guided on... a) Same guideways. b) Different guideways. c) Any of the above. d) Not guided on guideways 9-. Slab milling can be performed more effectively by milling machine. a) Horizontal. b) Vertical. c) Can't say anything. d) None of the mentioned. 10-Cutting T-slots can be performed more effectively by milling machine. a) Horizontal. b) Vertical. c) Can't say anything. d) None of the mentioned.
We have a rectangular piece. We wish to manufacture a parallel slot along thepiece in a vertical milling machine and 50 cm from the edge. The width of the slot is 40 mm. TheDepth of the slot is 25 mm. For this, several rough cutting steps and aFine cut with a depth of 0.20 mm. The depth for each of the steps ofrough cut is limited to 1.75 mmAditional information:What is the number of blades used for the rough cutting steps?What is the number of blades used for the fine cutting step?
Q1. The part shown below will be turned in two machining steps. In the first step a length of (50 + 50) = 100 mm will be reduced from Ø100 mm to Ø80 mm and in the second step a length of 50 mm will be reduced from Ø80 mm to Ø60 mm. Calculate the required total machining time T with the following cutting conditions: Cutting speed V=80 m/min, Feed is f=0.8 mm/rev, Depth of cut 3 mm per pass. Ø100 Ø80 Ø60 50 50
A NC lathe cuts two passes across a cylindrical workpiece under automatic cycle. The operator loads and unloads the machine. The starting diameter of the work is 3.00 in and its length = 10 in. The work cycle consists of the following steps (with element times given in parentheses where applicable): 1 - Operator loads part into machine, starts cycle (1.00 min); 2 - NC lathe positions tool for first pass (0.10 min); 3 - NC lathe turns first pass (time depends on cutting speed); 4 - NC lathe repositions tool for second pass (0.4 min); 5 - NC lathe turns second pass (time depends on cutting speed); and 6 - Operator unloads part and places in tote pan (1.00 min). In addition, the cutting tool must be periodically changed. This tool change time takes 1.00 min. The feed rate = 0.007 in/rev and the depth of cut for each pass = 0.100 in. The cost of the operator and machine = $39/hr and the tool cost = $2.00/cutting edge. The applicable Taylor tool life equation has parameters: n = 0.26 and…