On a recent quiz, the class mean was 76 with a standard deviation of 4.8. Calculate the z-score (to 4 decimal places) for a person who received score of 79. z-score: Is this unusual? O Unusual O Not Unusual

MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
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### Z-Score Calculation and Analysis

#### Problem Statement:
On a recent quiz, the class mean was 76 with a standard deviation of 4.8. Calculate the z-score (to 4 decimal places) for a person who received a score of 79.

#### Calculation of Z-Score:
To find the z-score, use the following formula:

\[ z = \frac{(X - \mu)}{\sigma} \]

where:
- \( X \) is the score,
- \( \mu \) is the mean,
- \( \sigma \) is the standard deviation.

For this problem:
- Mean (\( \mu \)) = 76
- Standard Deviation (\( \sigma \)) = 4.8
- Score (\( X \)) = 79

**Formula Application:**
\[ z = \frac{(79 - 76)}{4.8} = \frac{3}{4.8} = 0.6250 \]

Enter the z-score in the provided input box.

**Z-Score Input Box:**
\[ \text{z-score:} \ \_\_\_\_\_\_ \]

#### Analysis:
Evaluate if the score is unusual by comparing the z-score with typical z-score thresholds. Generally, in a normal distribution:
- A z-score less than -2 or greater than +2 is considered unusual.

#### Decision:
- Check the appropriate option based on the calculated z-score.

**Options:**
- Unusual 
- Not Unusual 

Given the calculated z-score of 0.6250, you should select "Not Unusual."

#### Diagram/Graph Explanation:
There are no diagrams or graphs associated with this text.

Feel free to utilize this as a guiding example to understand and calculate z-scores as well as analyze the results.
Transcribed Image Text:### Z-Score Calculation and Analysis #### Problem Statement: On a recent quiz, the class mean was 76 with a standard deviation of 4.8. Calculate the z-score (to 4 decimal places) for a person who received a score of 79. #### Calculation of Z-Score: To find the z-score, use the following formula: \[ z = \frac{(X - \mu)}{\sigma} \] where: - \( X \) is the score, - \( \mu \) is the mean, - \( \sigma \) is the standard deviation. For this problem: - Mean (\( \mu \)) = 76 - Standard Deviation (\( \sigma \)) = 4.8 - Score (\( X \)) = 79 **Formula Application:** \[ z = \frac{(79 - 76)}{4.8} = \frac{3}{4.8} = 0.6250 \] Enter the z-score in the provided input box. **Z-Score Input Box:** \[ \text{z-score:} \ \_\_\_\_\_\_ \] #### Analysis: Evaluate if the score is unusual by comparing the z-score with typical z-score thresholds. Generally, in a normal distribution: - A z-score less than -2 or greater than +2 is considered unusual. #### Decision: - Check the appropriate option based on the calculated z-score. **Options:** - Unusual - Not Unusual Given the calculated z-score of 0.6250, you should select "Not Unusual." #### Diagram/Graph Explanation: There are no diagrams or graphs associated with this text. Feel free to utilize this as a guiding example to understand and calculate z-scores as well as analyze the results.
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