On a one lane road, a person driving a car at v1 = 58 mi/h suddenly notices a truck 1.1 mi in front of him. That truck is moving in the same direction at v2 = 35 mi/h. In order to avoid a collision, the person has to reduce the speed of his car to v2 during time interval Δt. The smallest magnitude of acceleration required for the car to avoid a collision is a. During this problem, assume the direction of motion of the car is the positive direction.
On a one lane road, a person driving a car at v1 = 58 mi/h suddenly notices a truck 1.1 mi in front of him. That truck is moving in the same direction at v2 = 35 mi/h. In order to avoid a collision, the person has to reduce the speed of his car to v2 during time interval Δt. The smallest magnitude of acceleration required for the car to avoid a collision is a. During this problem, assume the direction of motion of the car is the positive direction.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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On a one lane road, a person driving a car at v1 = 58 mi/h suddenly notices a truck 1.1 mi in front of him. That truck is moving in the same direction at v2 = 35 mi/h. In order to avoid a collision, the person has to reduce the speed of his car to v2 during time interval Δt. The smallest magnitude of acceleration required for the car to avoid a collision is a. During this problem, assume the direction of motion of the car is the positive direction.
1. Use the expressions you entered in parts (c) and (f) and enter an expression for a in terms of d, v1, and v2.
a = ( v2 - v1 )/Δt
| Δt = ( 2 ) ( d )/( v1 - v2 ) |
2. Calculate the value of a in meters per second squared.
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