### Physics Problem: Multiple-Concept Example**Problem Statement:**Multiple-Concept Example 9 reviews the concepts that are important in this problem. A drag racer, starting from rest, speeds up for 424 m with an acceleration of +21.9 m/s². A parachute then opens, slowing the car down with an acceleration of -5.11 m/s². How fast is the racer moving 316 m after the parachute opens?---**Input Fields:**- **Number:** [ ] (Input box for numerical value)- **Units:** [ ] (Dropdown menu for unit selection)---**Explanation:**This problem involves understanding and applying concepts of kinematics, specifically the use of constant acceleration equations. The scenario describes a two-phase motion:1. Acceleration from rest to a specified distance.2. Deceleration after the parachute opens, over another specified distance.We can use the following kinematic equations to solve the problem:1. \(v_f^2 = v_i^2 + 2a d\) for both phases of the motion.**Phase 1 (Acceleration):**- Initial velocity (\(v_i\)) = 0 m/s (starting from rest)- Distance (\(d\)) = 424 m- Acceleration (\(a\)) = +21.9 m/s²**Phase 2 (Deceleration):**- Distance (\(d\)) = 316 m- Acceleration (\(a\)) = -5.11 m/s²By calculating the final velocity at the end of phase 1 and using it as the initial velocity for phase 2, you can find the speed of the racer 316 m after the parachute opens.

Name: ### Physics Problem: Multiple-Concept Example**Problem Statement:**Mu
Uploaded: 2024-03-05T11:56:34.000Z
Channel: Bartleby
Description: ### Physics Problem: Multiple-Concept Example**Problem Statement:**Multiple-Concept Example 9 reviews the concepts that are important in this problem. A drag racer, starting from rest, speeds up for 424 m with an acceleration of +21.9 m/s². A parach