On a one lane road, a person driving a car at v = 78 mi/h suddenly notices atruck 0.65 mi in front of him. That truck is moving in the same direction at v, = 41 mi/h. In order toavoid a collision, the person has to reduce the speed of his car to v2 during time interval At. Thesmallest magnitude of acceleration required for the car to avoid a collision is a. During this problem,assume the direction of motion ofhe car is the positive direction. Refer to the figure. O Enter an expression, in terms of defined quantities, for the distance, Ax,, traveled by the truck during the time interval AtFAx2789.НOMEBAtd.1A 46.a

Initial speed of the car is v1 = 78 mi/h Truck is moving at a speed of v2 = 41 mi/h Distance…

Answered: On a one lane road, a person driving a…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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On a one lane road, a person driving a car at v1 = 58 mi/h suddenly notices a truck 1.1 mi in front of him. That truck is moving in the same direction at v2 = 35 mi/h. In order to avoid a collision, the person has to reduce the speed of his car to v2 during time interval Δt. The smallest magnitude of acceleration required for the car to avoid a collision is a. During this problem, assume the direction of motion of the car is the positive direction. 1. Use the expressions you entered in parts (c) and (f) and enter an expression for a in terms of d, v1, and v2. a = ( v2 - v1 )/Δt Δt = ( 2 ) ( d )/( v1 - v2 ) 2. Calculate the value of a in meters per second squared.
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