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- 1). The susceptibility of FeCl₂ obeys the Curie-Weiss law over the temperature range 90 K to room temperature (293K), with 0 =48K. Its molecular susceptibility at room temperature is 1.475 1022 emu/Oe g mol). (Use: N= 6.022 x 1023 atoms/g-mol, KB= 1.38 × 10-¹6 erg/K) (a) Show that the effective magnetic moment is 5.4 µB. (b) Show that the value of J is 2.25. (c) At an applied field of 8000 Oe, what is the value of the molecular field at 0 °C ?Consider the followity pairs succntly had infinced spectroscope Could me either which is which ми ·OH of moleculer. Staff 30 O V-7: 500-OH -ова Ч OB₁ OTBS !.... OTBS ? n. мож .OTBS OTBI ова B₂ В Этски iPr Net6) What is the density of NaCl given that and rci = 181pm. Show your calculations below. rNa+ = 102pm Hint: Edge length of an unit cell of NaCl, d = 2rci +2rNa+, Volume = d³ Mass of NaCl unit cell = (58.54g/formula unit) x (# of 'units of NaCl' in a unit cell) 6.022 x 1023 units/ formula unit Density = mass/volume10 - Suponha que um complexo cúbico tenha a fórmula MX5Y3 onde X e Y são ligantes diferentes. Esboce as estruturas de todos os isômeros geométricos possíveis.(a) A silicon sample maintained at T = 300 K is uniformly doped with Nd = 1016cm-3 donors. Calculate the resistivity of the sample.app.101edu.co erbilt Universit... M Inbox (2) - esmat.h... Lobby | Top Hat Aktiv Chemistry D2L Homepage - Vande... M Gmail Handshake VYES - Vanderbilt - S... Question 14 of 22 Aluminum nitrate forms a white crystalline hydrate with the formula AI(NO3)3 nH₂O(s). If this hydrate is heated to a high enough temperature, H₂O(g) can be driven off, leaving the anhydrous salt AI(NO3)3(S). A 15.152-gram sample of the hydrate was heated to drive off the water, leaving Al(NO3)3(s) with a mass of 8.603 grams. Calculate the value of n in Al(NO3)3.nH₂O(S). Course HomGive a clear explanation handwritten answer...explain each point...2. A three-point loading scheme for measuring the stress-strain behavior and flexural strength, σF, (stress at fracture) of brittle ceramics for rectangular and circular cross sections materials are shown below. 3FfL = πR³ 2bd2 (depending on the FfL The flexural strength σF, can be calculated as: σFƒ cross section shape). = Calculate the ceramic flexural strength when Fƒ=1030 N, L=3.5 cm and 2R=b=d=1 cm and define which structure is stronger. Show your work. Note when you calculate, don't forget to unit conversion! Ff R Compression TensionSEE MORE QUESTIONS